如何比較javascript中多個數組的長度

Question

如何比較javascript中多個數組的長度。

Answer 1

function compareArraysLength(args) { 
    // The argument should be an array that contain arrays 
    var arrays = args; 
    var noOfElements = arrays.length; 
    var currentIndex = 0; 

    while (currentIndex < noOfElements) { 
     arrays.forEach(function(arg) { 
      if (arrays[currentIndex].length !== arg.length) { 
       throw new Error('All arrays must be of the same length'); 
      } 
     }); 
     currentIndex += 1; 
    } 
} 

我認爲這將是最好的。謝謝@rajesh

function compareArraysLength(args) { 
    return args.every(x=>x.length=== args[0].length) 
} 

Answer 2

Array.prototype.every()也可用於：

var array1 = [[1, 2, 3], [2, 3, 4, 5]]; 
 
var array2 = [[1, 2, 3], [2, 3, 4]]; 
 

 
function compareArraysLength(element, index, array) { 
 
    return element.length === array[0].length; 
 
} 
 

 
console.log(array1.every(compareArraysLength)); 
 
console.log(array2.every(compareArraysLength));