Python - 用字母和數字解析字符串不被阻塞在一起

Question

我在解析出包含字母和數字的字符串並獲取列表時遇到了問題。例如：

>>> s = '105Bii2016' 
>>> foo(s) 
['105', 'Bii', '2016'] 

現在我只能這樣做，如果數字是一起：

def foo(s): 
    num, letter = '', '' 
    for i in s: 
     if i.isdigit(): 
      num += i 
     else: 
      letter += i 
    return [letter, num] 

而當我把這個：

>>> s = '1234gdfh1234' 

>>> foo(s) 

['gdfh', '12341234'] 

Answer 1

如何itertools.groupby：

>>> s = '1234gdfh1234' 
>>> from itertools import groupby 
>>> print [''.join(v) for k,v in groupby(s,str.isdigit)] 
['1234', 'gdfh', '1234'] 

---

另一種解決方案使用正則表達式：

>>> print [x for x in re.split(r'(\d+)',s) if x] 
['1234', 'gdfh', '1234'] 

Answer 2

>>> from re import split 
>>> s = '1234gdfh1234' 
>>> [i for i in split(r'(\d+)',s) if i] 
['1234', 'gdfh', '1234']