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如何獲取內置方法的簽名? 例:字典()得到(K)獲取內置方法簽名 - Python
>> a = dict().get
>> a
<built-in method get of dict object at 0x1003aafd0>
>> a.__doc__
'D.get(k[,d]) -> D[k] if k in D, else d. d defaults to None.'
>> import inspect
>> inspect.getargspec(a)
TypeError: <built-in method get of dict object at 0x100377250> is not a Python function
我想看到的結果是這樣的
>> a.some_function()
('key', 'default'=None)
[如何獲取內建Python類構造函數的參數列表?](http://stackoverflow.com/questions/7628081/how-to-get-arguments-list-of-a-built -in-python-class-constructor) – ChristopheD
相關:http://bugs.python.org/issue1748064總結:目前你不能(在CPython中)。 – ChristopheD