2017-09-10 86 views
-1

使用pdo將數據插入表(mysql)時出現此錯誤。
這裏是我的代碼:無效的參數號:插入數據時未定義參數

$stmt = $this->db->prepare('INSERT INTO t_user (UserEmail, UserPassword, UserFirstName, UserLastName, UserSex, UserPhoneNumbers, UserNationalIdCardNo 
, UserBirthday, UserAddress, UserDetails, UserRoles, UserDecription) VALUES (:UserEmail, :UserPassword, :UserFirstName, :UserLastName, :UserSex, :UserPhoneNumbers 
, :UserNationalIdCardNo, :UserBirthday, :UserAddress, :UserDetails, :UserRoles, :UserDecription)'); 
     $stmt->bindValue(':UserEmail', $entity->UserEmail); 
     $stmt->bindValue(':UserPassword', md5($entity->UserPassword)); 
     $stmt->bindValue(':UserFirstName', $entity->UserFirstName); 
     $stmt->bindValue(':UserLastName', $entity->UserLastName); 
     $stmt->bindValue(':UserSex', $entity->UserSex); 
     $stmt->bindValue(':UserPhoneNumbers', json_encode($entity->UserPhoneNumbers)); 
     $stmt->bindValue(':UserNationalIdCardNo', $entity->UserNationalIdCardNo); 
     $stmt->bindValue(':UserBirthday', $entity->UserBirthday); 
     $stmt->bindValue(':UserAddress', $entity->UserAddress); 
     $stmt->bindValue(':UserDetails', $entity->UserDetails); 
     $stmt->bindValue(':UserRoles', json_encode($entity->UserRoles)); 
     $stmt->bindValue(':UserDescription', $entity->UserDescription); 
     $result = $stmt->execute(); 

請幫我

+2

'UserDescription' ='UserDecription'! – tkausl

+0

@tkausl解決了。非常感謝! –

回答

0

你拼寫:UserDecription,在查詢中,它應該是:UserDescription

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