在Android的SQLite表填充不正確

Question

我有一個有線問題。 我寫了一個使用sqlite的代碼。這是相關線路：

private final String DB_NAME = "cus"; 
    private final String TABLE_NAME = "cus2"; 
    SQLiteDatabase customersDB2 = null; 
    /** Called when the activity is first created. */ 
    private void mFillDbsTable(){ 
     try { 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (1, 'the ', 'ה- ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (2, 'of ', 'של ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (3, 'to ', 'אל ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (4, 'and ', 'ו - ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (5, 'a ', 'מופיע לפני שם עצם ביחיד ללא הא הידיעה ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (6, 'in ', 'בתוך ');"); 
      customersDB2.execSQL("INSERT INTO " + TABLE_NAME + " Values (7, 'for ', 'עבור ');"); 
    ................ 
    } 

    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_learn); 
     try { 
      customersDB2 = this.openOrCreateDatabase( DB_NAME, MODE_PRIVATE, null); 
      customersDB2.execSQL("CREATE TABLE " + 
        TABLE_NAME + 
        " (Block INT," + 
        " Name VARCHAR, Street VARCHAR);"); 
      mFillDbsTable(); 
}catch (SQLiteException se) { 
      Log.e(getClass().getSimpleName(), "create/Open the database problem"); 
} 

現在，當我問查詢：

correctAnswer=oneTOfour.nextInt(4); 
    Toast.makeText(this,"correctAnswerק"+correctAnswer,Toast.LENGTH_SHORT).show(); 
    correctAnswerTHE_ANSWER =(r.nextInt(1000)) + 1; 
    Toast.makeText(this,"correctAnswerTHE_ANSWER"+correctAnswerTHE_ANSWER,Toast.LENGTH_SHORT).show(); 

     ArrayList<String> results = new ArrayList<String>(); 
    Cursor c = customersDB2.rawQuery("SELECT Name, Street FROM " + 
      TABLE_NAME + 
      " where Block = 66 ", null); 


    if (c != null) { //true 

     Toast.makeText(this,"c.getColumnIndex(Name)" + c.getColumnIndex("Name"),Toast.LENGTH_SHORT).show(); //got 0!! 
     if (c.moveToFirst()) { 
      do { 

       name = c.getString(c.getColumnIndex("Name")); 
       street = c.getString(c.getColumnIndex("Street"));   
       results.add(name + ", " + street); 
      }while (c.moveToNext()); 
     } 
    } 

    else{ 
     Toast.makeText(this,"null2",Toast.LENGTH_SHORT).show(); 
    } 


    question.setText(name); //this is null 

}

它沒有到達第二，如果

也許是我第一次跑這個應用程序只有2列。 我試圖打開其他項目，改變表的名字..沒有工作。 有些想法？

Answer 1

"SELECT Name, Street FROM " ... 

當你的名字，你要選擇字段，它返回它們的順序，所以Name是第一列，或0。

如果您希望它們按照您創建它們的順序進行操作，請改爲使用SELECT * FROM。

問題是，它們的順序是什麼？您已經使用c.getColumnIndex()，所以他們的順序沒有意義。

Answer 2

可能與您在插入中使用的UTF非標準字符有關。你應該嘗試插入使用ContentValues，如：

ContentValues row = new ContentValues(); 
row.put("Name", "blah"); 
row.put("Street", "your utf strings"); 
row.put("Block", 1); 
long id = db.insert(TABLE_NAME, null, row);