基本的T-sql問題

我有一個邀請表。喜歡這個;基本的T-sql問題

Email   CreateDate 
[email protected]  2011-03-04 10:10:46.273 
[email protected]  2011-03-10 12:06:26.673 
[email protected]  2011-03-20 12:06:26.673 
[email protected]  2011-03-10 12:06:26.673

如何返回？

[email protected]  2011-03-04 10:10:46.273 1 
[email protected]  2011-03-10 12:06:26.673 1 
[email protected]  2011-03-20 12:06:26.673 2

來源

2011-04-07 ozkank

這可以由許多人在這裏回答。你寫了什麼SQL？ – shahkalpesh 2011-04-07 07:14:43

確實是「基本」。你有什麼嘗試？ – RichardTheKiwi 2011-04-07 07:23:35

SELECT Email, Max(CreateDate), Count(CreateDaate) FROM YourTable Group By Email.

來源

2011-04-07 07:15:24

select Email, max(CreateDate), count(*) 
from Invitation 
group by Email

來源

2011-04-07 07:15:59 mousio

您可以使用下面的複雜其一也。因此你可以通過子句學習分區。

select a.email,max(Date),max(a.rn) from (select email,date,ROW_NUMBER() over(partition by email order by email)rn from #a)a group by email

來源

2011-04-07 11:45:41 Luniam

基本的T-sql問題

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