我該如何將幾個動作<T>合併爲一個單獨的動作<T>在C＃中？

Question

如何在循環中構建動作動作？解釋（抱歉它是如此冗長）

我有以下幾點：

public interface ISomeInterface { 
    void MethodOne(); 
    void MethodTwo(string folder); 
} 

public class SomeFinder : ISomeInterface 
{ // elided 
} 

和一類使用上述：

public Map Builder.BuildMap(Action<ISomeInterface> action, 
          string usedByISomeInterfaceMethods) 
{ 
    var finder = new SomeFinder(); 
    action(finder); 
} 

我可以使用其中任一調用它，它的工作原理很好：

var builder = new Builder(); 

var map = builder.BuildMap(z => z.MethodOne(), "IAnInterfaceName"); 
var map2 = builder(z => 
        { 
        z.MethodOne(); 
        z.MethodTwo("relativeFolderName"); 
        }, "IAnotherInterfaceName"); 

我該如何以編程方式構建第二個實現？即，

List<string> folders = new { "folder1", "folder2", "folder3" }; 
folders.ForEach(folder => 
       { 
       /* do something here to add current folder to an expression 
        so that at the end I end up with a single object that would 
        look like: 
        builder.BuildMap(z => { 
            z.MethodTwo("folder1"); 
            z.MethodTwo("folder2"); 
            z.MethodTwo("folder3"); 
            }, "IYetAnotherInterfaceName"); 
       */ 
       }); 

我一直在想我需要一個

Expression<Action<ISomeInterface>> x 

或類似的東西，但對我的生活，我沒有看到如何構建我想要的東西。任何想法將不勝感激！

Answer 1

這真的很容易，因爲代表們已經播：

Action<ISomeInterface> action1 = z => z.MethodOne(); 
Action<ISomeInterface> action2 = z => z.MethodTwo("relativeFolderName"); 
builder.BuildMap(action1 + action2, "IAnotherInterfaceName"); 

或者，如果你已經得到了他們的集合，因爲某些原因：

IEnumerable<Action<ISomeInterface>> actions = GetActions(); 
Action<ISomeInterface> action = null; 
foreach (Action<ISomeInterface> singleAction in actions) 
{ 
    action += singleAction; 
} 

甚至：

IEnumerable<Action<ISomeInterface>> actions = GetActions(); 
Action<ISomeInterface> action = (Action<ISomeInterface>) 
    Delegate.Combine(actions.ToArray());