我已經看到了幾個SO帖子,這顯然與我的問題有關,但他們似乎都沒有做我想做的事情。我可以使用JQuery代碼模擬超鏈接的點擊嗎?
我有一個嵌套的結構,以顯示在報告層次(業務單元和品牌):
<tr class="BrandRow1">
<td>
</td>
</tr>
<tr class='BrandRow1 StoreRow1'>
...
</tr>
<tr class='BrandRow1 StoreRow2'>
...
</tr>
這個佈局中我使用A
標記來顯示/隱藏「孩子」的內容(通過使用。的class
屬性
上的負載,我想告訴所有的「節點」如果$('.StoreRow2').length
小於說4
我用一個函數來做到的觸發:
// Allow an item to toggle other items' visibility
$(".VisibilityToggle").click(function() {
var ControlledClass = findClass($(this), "Toggles-");
if (ControlledClass != "") {
$("." + ControlledClass).toggle();
var Text = $(this).attr("rel");
if (Text != "") $(this).attr("rel", $(this).attr("rev")).attr("rev", Text).text(Text);
}
return false;
});
我想要做的就是通過從JS代碼調用這個觸發'切換'打開。
我以爲像'$(「。VisibilityToggle」)。click()`會做我想要的東西,但這似乎並沒有在我的代碼工作,但確實如果我通過JS手動調用它控制檯在Chrome中。我懷疑它與我的代碼在事件綁定到頁面之前正在運行。
您能否協助?
感謝您的閱讀。
E.g.標記
...
<tr class='BrandRow TRBrand_2'>
<td class="Level0">
<p>
<a id="DesktopApp0_ctl00_rptReportBrand_ctl01_A_Brand" rel="-" rev="+" class="button toggleButton SummaryToggle VisibilityToggle Toggles-BrandId_2">+</a> <strong>Brand2</strong>
</p>
</td>
<td>
<p>
34</p>
</td>
<td>
<p>
21</p>
</td>
<td>
<p>
22</p>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
0.0%</p>
</td>
<td>
<p>
1
</p>
</td>
<td>
<p>
34.0
</p>
</td>
</tr>
<tr class='SiteRow BrandId_2 TRStore_10'>
<td class="Level1">
<p>
<a id="DesktopApp0_ctl00_rptReportBrand_ctl01_rptSites_ctl00_A_Site" rel="-" rev="+" class="button toggleButton SummaryToggle VisibilityToggle Toggles-TRSiteUser_10">+</a> <span class="Bold">BrandX - Store 10</span>
</p>
</td>
<td>
<p>
14</p>
</td>
<td>
<p>
9</p>
</td>
<td>
<p>
8</p>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
0.0%</p>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
0.0
</p>
</td>
</tr>
<tr class='UserRow TRStoreUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Clarke Kent
</p>
</td>
<td>
<p>
3</p>
</td>
<td>
<p>
3</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_3">1</span><span class=" d5_3">2</span><span class=" d5_3">3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Alexie Sayle
</p>
</td>
<td>
<p>
2</p>
</td>
<td>
<p>
2</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_2">1</span><span class=" d5_2">2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Anders Bottom
</p>
</td>
<td>
<p>
1</p>
</td>
<td>
<p>
1</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_1">1</span><span>2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Daniella Ecclescake
</p>
</td>
<td>
<p>
1</p>
</td>
<td>
<p>
1</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_1">1</span><span>2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Mark E Smith
</p>
</td>
<td>
<p>
2</p>
</td>
<td>
<p>
1</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_1">1</span><span>2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Matthew Bannister
</p>
</td>
<td>
<p>
1</p>
</td>
<td>
<p>
1</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span class=" d5_1">1</span><span>2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
<tr class='UserRow TRSiteUser_10'>
<td class="Level2">
<p>
<img src="/img/icons/spacer.png" alt=" " />
Raj Patel
</p>
</td>
<td>
<p>
3</p>
</td>
<td>
<p>
0</p>
</td>
<td colspan="3" class="Drive5Graphic">
<span>1</span><span>2</span><span>3</span><span>4</span><span>5</span><span class=" plus">+</span>
</td>
<td>
<p>
0</p>
</td>
<td>
<p>
∞</p>
</td>
</tr>
...
是的,你可以。 $(linkObject).click() – reporter 2011-06-16 11:30:57
正如我在我的問題中提到的,.click()在我的頁面中不起作用。我認爲它是在事件被綁定之前調用它的東西(我已經把我的調用放在$(document).ready(...);;中的.trigger/.click),因爲如果我通過調用函數Chrome中的JS控制檯,它的工作原理與您所說的完全相同。百思不得其解。 – 5arx 2011-06-16 11:36:43
我不知道.ABrand是,請給更多的標記 – ridcully 2011-06-16 11:41:58