解析不成功

Question

以下解析器正在返回空值。 任何人都可以幫助我...

-(IBAction)search:(id)sender 
{ 
    NSString *webserviceURL = [NSString stringWithFormat:@"https://maps.googleapis.com/maps/api/place/textsearch/json?query=Delhi&sensor=true&key=AIzaSyCGeIN7gCxU8baq3e5eL0DU3_JHeWyKzic"]; 
    NSURL *finalURl = [NSURL URLWithString:webserviceURL]; 
    NSData *data = [NSData dataWithContentsOfURL:finalURl]; 
    NSString *data1 = [NSString stringWithUTF8String:[data bytes]]; 
    NSLog(@"Result is :%@", data1); 
    NSError * error; 
    NSDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers|NSJSONReadingAllowFragments error:& error]; 

    NSLog(@"Result is :%@", json); 
} 

Answer 1

試試這個代碼。

NSURL * url=[NSURL URLWithString:@"https://maps.googleapis.com/maps/api/place/textsearch/json?query=Delhi&sensor=true&key=AIzaSyCGeIN7gCxU8baq3e5eL0DU3_JHeWyKzic"]; 

NSData * data=[NSData dataWithContentsOfURL:url]; 

NSError * error; 
NSMutableDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:NSJSONReadingMutableContainers|NSJSONReadingAllowFragments error:& error]; 

NSLog(@"Result is :%@", json); 


NSArray * responseArr = json[@"results"]; 

for(NSDictionary * dict in responseArr) 
{ 
     [firstArray addObject:[dict valueForKey:@"firstkey"]]; 
     [secondArray addObject:[dict valueForKey:@"secondkey"]];  
} 

    NSLog(@"%@",firstArray); 
    NSLog(@"%@",secondArray); 

和陣列得到您的數據後，你想要做什麼

使用此代碼，因爲它是和替換你的代碼，這將讓你的JSON響應thius代碼。