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我已經搜索了很多，找不到解決方案。類似的線程也在我們的堆棧overflow.But沒有use.So我創建了一個新的線程。Spring MVC + Jquery Ajax顯示406錯誤？
我的JSP是，
<boby>
<% System.out.println("request.getContextPath() : "+request.getContextPath()); %>
<h1>Spring_JsonTest Example</h1>
<table>
<tr><td colspan="2"><div id="error" class="error"></div></td></tr>
<tr><td>Enter your name : </td><td> <input type="text" id="name"><br/></td></tr>
<tr><td>Your Education : </td><td> <input type="text" id="education"><br/></td></tr>
<tr><td colspan="2"><input type="button" value="Add Users" onclick="doAjaxPost()"><br/></td></tr>
<tr><td colspan="2"><div id="info" class="success"></div></td></tr>
</table>
</body>
我jQuery是，
function doAjaxPost() {
// get the form values
var name = $('#name').val();
var education = $('#education').val();
$.ajax({
type: "POST",
url: contexPath + "/AddUser.html",
data: "name=" + name + "&education=" + education,
success: function(response){
// we have the response
if(response.status == "SUCCESS"){
userInfo = "<ol>";
for(i =0 ; i < response.result.length ; i++){
userInfo += "<br><li><b>Name</b> : " + response.result[i].name +
";<b> Education</b> : " + response.result[i].education;
}
userInfo += "</ol>";
$('#info').html("User has been added to the list successfully. " + userInfo);
$('#name').val('');
$('#education').val('');
$('#error').hide('slow');
$('#info').show('slow');
}else{
errorInfo = "";
alert("Success response : "+response)
for(i =0 ; i < response.result.length ; i++){
errorInfo += "<br>" + (i + 1) +". " + response.result[i].code;
}
$('#error').html("Please correct following errors: " + errorInfo);
$('#info').hide('slow');
$('#error').show('slow');
}
},
error: function(xhr, ajaxOptions, thrownError)
alert("status :"+xhr.status+"\nthrownError : "+thrownError+"\nresponseText : "+xhr.responseText);
alert('Error: ' +xhr.description);
}
});
}
我的控制器是，
@Controller
public class UserController {
private List<User> userList = new ArrayList<User>();
@RequestMapping(value="/AddUser.html",method=RequestMethod.POST)
public @ResponseBody JsonResponse addUser(@ModelAttribute(value="user") User user, BindingResult result){
System.out.println("Add user POST method");
JsonResponse res = new JsonResponse();
ValidationUtils.rejectIfEmpty(result, "name", "Name can not be empty.");
ValidationUtils.rejectIfEmpty(result, "education", "Education not be empty");
if(!result.hasErrors()){
userList.add(user);
res.setStatus("SUCCESS");
res.setResult(userList);
}else{
res.setStatus("FAIL");
res.setResult(result.getAllErrors());
}
return res;
}
}
我JsonResponse.java是，
package com.tps.jsonTest.service;
public class JsonResponse {
private String status = null;
private Object result = null;
public String getStatus() {
return status;
}
public void setStatus(String status) {
this.status = status;
}
public Object getResult() {
return result;
}
public void setResult(Object result) {
System.out.println("Result : "+result.toString());
this.result = result;
}
}
和我User.java是，
package com.tps.jsonTest.service;
public class User {
private String name = null;
private String education = null;
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEducation() {
return education;
}
public void setEducation(String education) {
this.education = education;
}
}
在我的控制檯，
Add user POST method
Name : Anand
Education : B.E
Result : [[email protected]]
Jar文件，
commons-logging-1.1.1.jar
jackson-core-asl-1.9.12.jar
jackson-mapper-asl-1.9.12.jar
log4j-1.2.9.jar
servlet-api-2.4.jar
spring-aop-3.2.2.RELEASE.jar
spring-beans-3.2.2.RELEASE.jar
spring-context-3.2.2.RELEASE.jar
spring-context-support-3.2.2.RELEASE.jar
spring-core-3.2.2.RELEASE.jar
spring-expression-3.2.2.RELEASE.jar
spring-web-3.2.2.RELEASE.jar
spring-webmvc-3.2.2.RELEASE.jar
在瀏覽器中的錯誤是，
我不能使用jquery解析對象，它會在error.Hope我們的堆棧用戶將幫助我。
好的答案肯定讚賞。謝謝。
你能後的圖像中的錯誤？這很難讀... – Thihara 2013-04-10 10:40:20
@Thihara'狀態：406'，'拋出錯誤：undefined'。 – 2013-04-10 10:43:05
你可以嘗試設置內容類型爲文本/ json – Satya 2013-04-10 10:43:52