Oracle複雜查詢：INSERT + SELECT CONNECT BY + ON DUPLICATE KEY

Question

我有一個表來計算字出現次數，WORD_COUNT(WORD, TOTAL)，它在另一個表上的觸發器中更新。這是在hierachichal查詢做過這樣的：字的

創建和總= 1：

INSERT INTO WORD_COUNT(TOTAL, WORD) 
    SELECT 1, TRANSLATE(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level), 
          'áéíóúÁÉÍÓÚ', 
          'aeiouAEIOU') 
    FROM DUAL 
    WHERE LENGTH(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level)) >= 5 
    CONNECT BY regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level) IS NOT NULL; 

這項工作完美的，它分裂一個短語（鳴叫）進言，將它們插入WORD_COUNT。

現在的問題是，當我想增加重複鍵上的總數（WORD是主鍵）時，我需要添加一個ON DUPLICATE KEY子句，該子句看起來與CONNECT BY子句似乎不太一樣。

此查詢不編譯：

INSERT INTO WORD_COUNT(TOTAL, WORD) 
    SELECT 1, TRANSLATE(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level), 
          'áéíóúÁÉÍÓÚ', 
          'aeiouAEIOU') 
    FROM DUAL 
    WHERE LENGTH(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level)) >= 5 
    CONNECT BY regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level) IS NOT NULL 
    ON DUPLICATE KEY UPDATE TOTAL=TOTAL+1; 

而這一次也不：

INSERT INTO WORD_COUNT(TOTAL, WORD) 
WITH WORDS(WORD) AS 
(SELECT DISTINCT 1, 
     TRANSLATE(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level), 
          'áéíóúÁÉÍÓÚ', 
          'aeiouAEIOU') 
    FROM DUAL 
    WHERE LENGTH(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level)) >= 5 
    CONNECT BY regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level) IS NOT NULL) 
SELECT WORD FROM WORD_COUNT 
ON DUPLICATE KEY UPDATE TOTAL = TOTAL + 1; 

由於這種情況正在發生一個高流量表的觸發器中，我想在解決這一單一的查詢，但也許是時候想一箇中間表，是嗎？

謝謝

Answer 1

這應該使用合併是可能的：

MERGE INTO WORD_COUNT WC 
USING 
(
    SELECT DISTINCT 1, 
     TRANSLATE(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level), 
          'áéíóúÁÉÍÓÚ', 
          'aeiouAEIOU') 
    FROM DUAL 
    WHERE LENGTH(regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level)) >= 5 
    CONNECT BY regexp_substr(:NEW.TWEET, '[^[:punct:]|[:space:]]+', 1, level) IS NOT NULL 
) NW 
ON (WC.WORD = NW.WORD) 
WHEN MATCHED THEN UPDATE SET WC.TOTAL = WC.TOTAL + 1 
WHEN NOT MATCHED THEN INSERT(TOTAL, WORD) VALUES(NW.TOTAL, NW.WORD); 

Answer 2

據我所知Oracle數據庫不支持「的重複鍵」的條款。你應該嘗試使用MERGE子句。

我認爲這是類似的問題：Oracle: ON DUPLICATE KEY UPDATE