這裏是給我找麻煩代碼:我想不通爲什麼會這樣對我的生活爲什麼在嘗試將重複對象添加到std :: set時會出現這個奇怪的錯誤?
Relation* Relation::relation_union(Relation* r) {
std::set<Tuple*>::iterator it1;
for (it1 = tuples.begin(); it1 != tuples.end(); it1++) {
r->tuples.insert(*it1); //this is where i insert into the set
}
return r;
}
。我用這段代碼得到了一個核心轉儲。
以下代碼可以很好地按字母順序排列我的集合中的元組(這是字符串的向量),但我認爲這是我的錯誤的來源,因爲它不知道每個元素相同時該做什麼:
編輯對代碼進行了更改。
struct comp {
bool operator()(const Tuple * lt, const Tuple * rt) {
for (unsigned i = 0; i < lt->values.size(); i++) {
std::string strl = lt->values[i];
std::string strr = rt->values[i];
if (strl != strr) {
return (strl < strr); // compares with the length
}
}
return false;
}
};
'元組' 來自下面的代碼:
Relation(){
name = "";
schema = new Schema();
tuples = std::set<Tuple*, comp>();
domain = std::set<std::string>();
}
std::string name;
Schema* schema;
std::set<Tuple*, comp> tuples;
std::set<std::string> domain;
}
這裏是我的堆棧跟蹤 - 這是不是非常有幫助,我:
Program received signal SIGABRT, Aborted.
0x00007ffff753b425 in raise() from /lib/x86_64-linux-gnu/libc.so.6
(gdb) bt
#0 0x00007ffff753b425 in raise() from /lib/x86_64-linux-gnu/libc.so.6
#1 0x00007ffff753eb8b in abort() from /lib/x86_64-linux-gnu/libc.so.6
#2 0x00007ffff7b9169d in __gnu_cxx::__verbose_terminate_handler()() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#3 0x00007ffff7b8f846 in ??() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#4 0x00007ffff7b8f873 in std::terminate()() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#5 0x00007ffff7b8f96e in __cxa_throw() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#6 0x00007ffff7b3c987 in std::__throw_out_of_range(char const*)() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#7 0x00007ffff7b7a453 in std::string::substr(unsigned long, unsigned long) const() from /usr/lib/x86_64-linux-gnu/libstdc++.so.6
#8 0x000000000040d889 in Input::getTokensValue (this=0x630460) at Input.cpp:91
#9 0x000000000040e812 in Lex::emit (this=0x7fffffffe130, tokenType=UNDEFINED) at Lex.cpp:268
#10 0x000000000040e12d in Lex::nextState (this=0x7fffffffe130) at Lex.cpp:106
#11 0x000000000040e026 in Lex::generateTokens (this=0x7fffffffe130, input=0x630460) at Lex.cpp:85
#12 0x000000000040da20 in Lex::Lex (this=0x7fffffffe130, filename=0x0) at Lex.cpp:17
#13 0x000000000040ea3e in main (argc=1, argv=0x7fffffffe248) at main.cpp:7
任何幫助將是非常讚賞。謝謝。
'std :: set'的一半是它不存儲重複項。有一套'Tuple'而不是那些指針有問題嗎? – chris
如果所有值相等,'comp :: operator()'返回什麼? –
除了@AlexChamberlain,請調高警戒級別。 – chris