2012-02-15 134 views
0

我正在學習編寫用於工作的Python腳本,並遇到一些問題。該腳本應該讀取一個文件,並將權限打印到電子郵件。我的問題是,當它嘗試調用permission()方法時出現錯誤,並且我不知道如何解決該問題。權限,Python腳本

Python代碼

import smtplib 
import os 
import stat 

result = "" 
def permission(file): 
     s = os.stat(file) 
     mode = s.st_mode 

     if(stat.S_IRUSR & mode): 
      ownerRead = 1 
      result += ownerRead 
     else: 
      ownerRead = 0 
      result += ownerRead 
     if(stat.S_IWUSR & mode): 
      ownerWrite = 1 
      result += ownerWrite 
     else: 
      ownerWrite = 0 
      result += ownerWrite 
     if(stat.S_IXUSR & mode): 
      ownerExecute = 1 
      result += ownerExecute 
     else: 
      ownerExecute = 0 
      result += ownerExecute 
     if(stat.S_IRGRP & mode): 
      groupRead = 1 
      result += groupRead 
     else: 
      groupRead = 0 
      result += groupRead 
     if(stat.S_IWGRP & mode): 
      groupWrite = 1 
      result += groupWrite 
     else: 
      groupWrite = 0 
      result += groupWrite 
     if(stat.S_IXGRP & mode): 
      groupExecute = 1 
      result += groupExecute 
     else: 
      groupExecute = 0 
      result += groupExecute 
     if(stat.S_IROTH & mode): 
      otherRead = 1 
      result += otherRead 
     else: 
      otherRead = 0 
      result += otherRead 
     if(stat.S_IWOTH & mode): 
      otherWrite = 1 
      result += otherWrite 
     else: 
      otherWrite = 0 
      result += otherWrite 
     if(stat.S_IXOTH & mode): 
      otherExecute = 1 
      result += otherExecute 
     else: 
      otherExecute = 0 
      result += otherExecute 
     return result 
to = '[email protected]' 
gmail_user = '[email protected]' 
gmail_pwd = 'pwd' 
smtpserver = smtplib.SMTP("smtp.gmail.com",587) 
smtpserver.ehlo() 
smtpserver.starttls() 
smtpserver.ehlo 
smtpserver.login(gmail_user, gmail_pwd) 
header = 'To:' + to + '\n' + 'From: ' + gmail_user + '\n' + 'Subject:permissions \n' 
print header 
values = permission(file) 
print values 
msg = header + values 
smtpserver.sendmail(gmail_user, to, msg) 
print 'done!' 
smtpserver.close() 

錯誤輸出

Traceback (most recent call last): 
    File "lastpart.py", line 83, in <module> 
    values = permission(file) 
    File "lastpart.py", line 15, in permission 
    s = os.stat(file) 
TypeError: coercing to Unicode: need string or buffer, type found 
+0

嘗試重命名你的函數的參數? 'file'已經是一個類型名稱,顯然,python也會因爲使用'file'參數而變得困惑。 – 2012-02-15 06:52:32

+1

@Ulrich:不,Python可以讓它們保持直線。但提問者不能。 – 2012-02-15 06:54:58

回答

3

這可以通過使用實際文件名的功能,而不是file內置式固定。

2
>>> file 
<type 'file'> 

名稱你比其他file可變的東西,實際上傳遞一個文件名給它。你從來沒有真正定義你傳遞給函數調用的東西,因此它不會因未定義的變量錯誤而崩潰的唯一原因是因爲Python恰好已經定義了內置該名稱的東西。