我想從URL中讀取XML中的天氣數據。 XML看起來像這樣:C#從XML中提取數據
<weatherdata>
<location>...</location>
<credit>...</credit>
<links>...</links>
<meta>...</meta>
<sun rise="2013-05-11T04:49:22" set="2013-05-11T21:39:03"/>
<forecast>
<text>...</text>
<tabular>
<time from="2013-05-11T01:00:00" to="2013-05-11T06:00:00" period="0">
<!--
Valid from 2013-05-11T01:00:00 to 2013-05-11T06:00:00
-->
<symbol number="2" name="Fair" var="mf/02n.03"/>
<precipitation value="0" minvalue="0" maxvalue="0.1"/>
<!-- Valid at 2013-05-11T01:00:00 -->
<windDirection deg="173.8" code="S" name="South"/>
<windSpeed mps="4.2" name="Gentle breeze"/>
<temperature unit="celsius" value="9"/>
<pressure unit="hPa" value="1004.2"/>
</time>
</tabular>
</forecast>
<observations>...</observations>
</weatherdata>
我對XML中的預測數據感興趣。我想從時間到時間,然後是天氣數據。例如,溫度是這樣寫的XML:
<temperature unit="celsius" value="9"/>
我想這樣的事情來提取數據:
string fromTime = time from(the attribute in the xml);
string fromTime =time to(the attribute in the xml);
string name = temperature(the attribute in the xml);
string unit =unit(the attribute in the xml);
int value = value(the attribute in the xml);
我創建示例代碼,能夠讀取的一切,但我不不知道如何提取我需要的數據。我現在的代碼看起來像這樣:
String URLString = "http://www.yr.no/place/Norway/Oslo/Oslo/Oslo/forecast.xml";
XmlTextReader reader = new XmlTextReader(URLString);
while (reader.Read())
{
switch (reader.NodeType)
{
case XmlNodeType.Element: // The node is an element.
Console.Write("" + reader.Name);
while (reader.MoveToNextAttribute()) // Read the attributes.
Console.Write(" " + reader.Name + "='" + reader.Value + "'");
Console.Write("\n");
Console.WriteLine("------------------------------");
break;
case XmlNodeType.Text: //Display the text in each element.
Console.WriteLine(reader.Value);
break;
case XmlNodeType.EndElement: //Display the end of the element.
Console.Write("</" + reader.Name);
Console.WriteLine(">");
break;
}
}
任何想法如何我只能提取天氣數據和時間?
您是否僅限於使用.Net 2.0或更早版本?如果沒有,我會建議使用Linq到XML。 – Gjeltema 2013-05-10 22:49:02