你可以通過你的數據數組這樣的循環:
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$yourData = array();
for($i = 0; $i < 5; $i++){
$yourData[] = array(
'title' => md5(rand()),
'description' => rand(0, 1)?'active':'banned',
'created_on' => rand(0, 1)?'now':'2014/12/31 14:51:52'
);
}
for($j = 0; $j < count($yourData); $j++) {
$title = $yourData[$j]["title"];
$description = $yourData[$j]["description"];
$created_on = $yourData[$j]["created_on"];
$sql = "INSERT INTO yourTable (title,description,created_on) VALUES ($title, $description, $created_on)";
if (mysqli_query($conn, $sql)) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . mysqli_error($conn);
}
mysqli_close($conn);
}
取決於您的數據庫連接上 - PDO,mysqli,mysql,一些框架? – Philipp
我已更新問題。我正在使用[this](http://www.w3schools.com/php/php_mysql_select.asp)教程來設置連接。 –