5
我試圖在按下按鈕時設置一個ViewState變量,但它僅在第二次點擊按鈕時才起作用。這裏是代碼隱藏:在回發上設置視圖狀態
protected void Page_Load(object sender, EventArgs e)
{
if (Page.IsPostBack)
{
lblInfo.InnerText = String.Format("Hello {0} at {1}!", YourName, DateTime.Now.ToLongTimeString());
}
}
private string YourName
{
get { return (string)ViewState["YourName"]; }
set { ViewState["YourName"] = value; }
}
protected void btnSubmit_Click(object sender, EventArgs e)
{
YourName = txtName.Text;
}
有什麼我失蹤?下面是設計文件的形式部分,就像POC非常基本的:
<form id="form1" runat="server">
<div>
Enter your name: <asp:TextBox runat="server" ID="txtName"></asp:TextBox>
<asp:Button runat="server" ID="btnSubmit" Text="OK" onclick="btnSubmit_Click" />
<hr />
<label id="lblInfo" runat="server"></label>
</div>
</form>
PS:樣品是非常簡單的,「使用txtName.Text
而不是ViewState的」不正確的答案,我需要在ViewState中的信息。