3
我查詢了數據庫,並將結果存儲到數組中。它看起來像這樣:PHP:用現有唯一值替換數組索引鍵
Array
(
[0] => Array
(
[Submission_ID] => 111
[First_Name] => Dylan
[Last_Name] => Taylor
[Abstract_Title] => Research 1
)
[1] => Array
(
[Submission_ID] => 222
[First_Name] => Michael
[Last_Name] => Jones
[Abstract_Title] => Research 2
)
[2] => Array
(
[Submission_ID] => 333
[First_Name] => Wills
[Last_Name] => Adams
[Abstract_Title] => Research 3
)
)
這是全部放在一個名爲$results
的變量中。目前,我在我的網頁上顯示的數據位,如下所示:
echo $results[0][Abstract_Title]
所有的工作,但是,它是方便,如果索引鍵是與提交ID代替:
Array
(
[111] => Array
(
[Submission_ID] => 111
[First_Name] => Dylan
[Last_Name] => Taylor
[Abstract_Title] => Research 1
)
[222] => Array
(
[Submission_ID] => 222
[First_Name] => Michael
[Last_Name] => Jones
[Abstract_Title] => Research 2
)
[333] => Array
(
[Submission_ID] => 333
[First_Name] => Wills
[Last_Name] => Adams
[Abstract_Title] => Research 3
)
)
所以我可以這樣做(否則我將不得不打印陣列只是爲了每次查找索引鍵):
echo $results[111][Abstract_Title]
任何想法? (我是編程新手。)我找到的最接近的答案是:php replace array id keys但我無法解決問題。我想到一個forloop
是最好的選擇?新的數組應該放在相同的變量還是新的變量中?
一個很好的解決方案! –
謝謝@Sougata .... –