2009-06-18 59 views
46
session.createQuery("Select attribute from GoodsSection tgs " + 
    "join gs.ascendants ags join ags.attributes attribute " + 
    "where attribute.outerId = :outerId and tgs = :section ") 
.setString("outerId", pOuterId) 
.setEntity("section", section) 
.setMaxResults(1) 
.uniqueResult(); 

「節點沒有任何數據類型」看起來好像沒什麼問題,但結果是這個HQL有什麼問題?

java.lang.IllegalStateException: No data type for node: org.hibernate.hql.ast.tree.IdentNode 
\-[IDENT] IdentNode: 'attribute' {originalText=attribute} 

    at org.hibernate.hql.ast.tree.SelectClause.initializeExplicitSelectClause(SelectClause.java:145) 
    at org.hibernate.hql.ast.HqlSqlWalker.useSelectClause(HqlSqlWalker.java:705) 
    at org.hibernate.hql.ast.HqlSqlWalker.processQuery(HqlSqlWalker.java:529) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:645) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229) 

爲什麼?怎麼了?

回答

76

您尚未定義「gs」別名。你只有「ags」和「tgs」。

-1

當出現此錯誤時,應該知道單詞或變量之間沒有找到空格或沒有空格。