Gallery Pro Table進入mysql的wordpress

Question

我怎樣才能達到Gallery Pro插件表進入mysql在wordpress？

我需要找到Gallery Pro插件查詢，以顯示幻燈片圖庫圖片在App通過REST API

在管理面板，我走進畫廊添加新的圖像與短代碼[WG id=1606] 使其一行到wp_posts表

當我添加圖片從PC將它添加新行post_parent = '1606'

但是當我添加圖像已歷經上傳到服務器時，它不添加任何行wp_posts表

Answer 1

我找到解決方案：

$lksg_Id = '1606'; 
    $TotalImg = get_post_meta($lksg_Id, 'lksg_total_images_count', true); 
    $lksg_Gallery_Settings = "lksg_Gallery_Settings_".$lksg_Id; 
    $lksg_AllPhotosDetails = unserialize(base64_decode(get_post_meta($lksg_Id, 'lksg_all_photos_details', true))); 
    // echo 'All Photos Details : <br /> ' . var_dump($lksg_AllPhotosDetails) . '<br /><br /><br />'; 
    if(count($lksg_Gallery_setting)) { 
     $lk_gallery_title  = $lksg_Gallery_setting['lk_gallery_title']; 
     $lk_show_image_label  = $lksg_Gallery_setting['lk_show_image_label']; 
     $lk_Gallery_Layout  = $lksg_Gallery_setting['lk_Gallery_Layout']; 
     $wgp_Color   = $lksg_Gallery_setting['wgp_Color']; 
     $lk_label_Color    =  $lksg_Gallery_setting['lk_label_Color']; 
     $lk_desc_font_Color   =  $lksg_Gallery_setting['lk_desc_font_Color']; 
     $lk_btn_Color    =  $lksg_Gallery_setting['lk_btn_Color']; 
     $lk_btn_font_Color  =  $lksg_Gallery_setting['lk_btn_font_Color']; 
     $lk_font_style   =  $lksg_Gallery_setting['lk_font_style']; 
     $lk_Custom_CSS   =  $lksg_Gallery_setting['lk_Custom_CSS']; 
     $lk_show_img_desc  =  $lksg_Gallery_setting['lk_show_img_desc']; 
     $lk_Light_Box   =  $lksg_Gallery_setting['lk_Light_Box']; 
     $lk_open_link   =  $lksg_Gallery_setting['lk_open_link']; 
     $lk_button_title  =  $lksg_Gallery_setting['lk_button_title']; 
    } 
    // echo 'Gallery setting : ' . var_dump($lksg_Gallery_setting) . '<br /><br /><br />'; 
    // echo 'Total Img : ' . var_dump($TotalImg) . '<br /><br /><br />'; 
    $results = array(); 
    if($TotalImg) { 
     foreach($lksg_AllPhotosDetails as $data) { 
      // echo 'data : <br /> ' . var_dump($data) . '<br /><br /><br />'; 
      $item = new stdclass(); 
      // $item->id = $data->ID; 
      $item->title = $data['lksg_image_label']; 
      $item->content = $data['img_desc']; 
      $item->image = $data['lksg_image_url']; 
      $item->tbn = $data['lksg_img_medium']; 
      $results[] = $item; 
     } 
    } 
    // Finally Return Array As Json String