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我試圖從地址簿中檢索聯繫人&在iOS視圖中以與iOS中的聯繫人應用程序相同的索引列表形式顯示它。我正在排序姓名上的聯繫人。如果姓氏爲空，那麼我的應用程序崩潰。這裏是我的代碼如果iOS 5的聯繫人姓氏爲空，則應用程序崩潰+
- (void)getAddressBookDataForUpdateRequest:(BOOL)isUpdateRequest {
if (self.peopleArray == nil) {
NSMutableArray *temp = [[NSMutableArray alloc]init];
self.peopleArray = temp;
}
if (self.batchUserArray == nil) {
NSMutableArray *temp = [[NSMutableArray alloc]init];
self.batchUserArray = temp;
}
row = [[NSMutableDictionary alloc] init];
words = [[NSMutableArray alloc]init];
ABAddressBookRef addressBook=ABAddressBookCreate();
CFArrayRef cfPeople=ABAddressBookCopyArrayOfAllPeople(addressBook);
CFMutableArrayRef cfPeopleMutable=CFArrayCreateMutableCopy(kCFAllocatorDefault, CFArrayGetCount(cfPeople), cfPeople);
CFArraySortValues(cfPeopleMutable, CFRangeMake(0, CFArrayGetCount(cfPeopleMutable)), (CFComparatorFunction)ABPersonComparePeopleByName, (void *)ABPersonGetSortOrdering());
NSArray *tempPeople=(__bridge NSArray *)cfPeopleMutable;
APP_DELGATE.people = [NSArray arrayWithArray:tempPeople];
peopleCount = [APP_DELGATE.people count];
lastCharacter = @"A";
if (peopleCount >0) {
int noOfRec = 0;
for (int i=0; i<peopleCount; i++) {
ABRecordRef record = (__bridge ABRecordRef)[APP_DELGATE.people objectAtIndex:i];
// Convert ABRecordRef to UserContactInfo object
UserContactInfo *user = [self getUserContactInfoFromABRecordRef:record isForUpdate:isUpdateRequest];
if (user != nil) {
currentCharacter = [[user.lastName substringToIndex:1]uppercaseString];
NSLog(@"Last: %@ :: Current:- %@",lastCharacter,currentCharacter);
if ([currentCharacter isEqualToString:lastCharacter]) {
[words addObject:user];
}
else {
row = nil;
row = [[NSMutableDictionary alloc] init];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:words forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
NSDictionary *dic = [NSDictionary dictionaryWithObjectsAndKeys:[self.batchUserArray mutableCopy],BATCH_DONE_KEY,[NSNumber numberWithBool:isUpdateRequest],@"isUpdateRequest", nil];
[[NSNotificationCenter defaultCenter] postNotificationName:BATCH_DONE_NOTIFICATION object:self userInfo:dic];
[self.batchUserArray removeAllObjects];
words = nil;
words = [[NSMutableArray alloc]init];
[words addObject:user];
NSLog(@"ASCII Value of %@ = %d :: Last Char %@ = %d",currentCharacter,[currentCharacter characterAtIndex:0],lastCharacter,[lastCharacter characterAtIndex:0]);
int lastCharAsciiValue = [lastCharacter characterAtIndex:0];
int currentCharAsciiValue = [currentCharacter characterAtIndex:0];
while ((lastCharAsciiValue +1) < (currentCharAsciiValue)) {
row = nil;
row = [[NSMutableDictionary alloc] init];
lastCharAsciiValue ++;
lastCharacter = [NSString stringWithFormat:@"%c",lastCharAsciiValue];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:[[NSMutableArray alloc]init] forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
}
}
lastCharacter = currentCharacter;
noOfRec++;
}
}
// For last char "z"
row = nil;
row = [[NSMutableDictionary alloc] init];
[row setValue:lastCharacter forKey:@"sectionTitle"];
[row setValue:words forKey:@"sectionRows"];
[self.peopleArray addObject:row];
[self.batchUserArray addObject:row];
NSLog(@"total rec count=%d",self.peopleArray.count);
NSDictionary *dic = [NSDictionary dictionaryWithObjectsAndKeys:self.batchUserArray,BATCH_DONE_KEY,[NSNumber numberWithBool:isUpdateRequest],@"isUpdateRequest", nil];
[[NSNotificationCenter defaultCenter] postNotificationName:BATCH_DONE_NOTIFICATION object:self userInfo:dic];
[self.batchUserArray removeAllObjects];
[[NSNotificationCenter defaultCenter]postNotificationName:TASK_DONE_NOTIFICATION object:self];
APP_DELGATE.allUsersArray = self.peopleArray;
}
else {
[[NSNotificationCenter defaultCenter]postNotificationName:NO_CONTACTS_AVAILABLE_NOTIFICATION object:nil];
}
CFRelease(addressBook);
}
如果姓是空的應用程序崩潰的
if ([currentCharacter isEqualToString:lastCharacter]) {
[words addObject:user];
}
我如何檢查是否姓是在索引列表中未署名的部分空&顯示它。 任何形式的幫助表示讚賞。在此先感謝