POST從jquery 1.8 $ .ajax返回304.錯誤的apache配置？

Question

我拍下面的POST請求遠程Apache服務器，託管小PHP腳本：

的POST：

var request = $.ajax({ 
    type: 'POST', 
    url: 'http://my.server.on.port/mmm.php', 
    data: { abc: "abcdefghijklmnopqrstuvwxyz" } }) 
    .done(function(data) { alert("success :"+data.slice(0, 100)); }); 

request.fail(function(jqXHR, textStatus) { 
    alert("Request failed: " + request.reponseText + " " + request.status +" " + request.statusText +" " +request.responseText ); 
}); 

mmm.php腳本：

<?php echo json_encode(array("first"=>"XXXXX","last"=>"YYYYY")); ?> 

httpd.conf文件：

ServerName my.server.on.port 
DocumentRoot "/var/www/html" 

<Directory "/var/www/html"> 
    Options Indexes FollowSymLinks 
    AllowOverride None 
    Order allow,deny 
    Allow from all 
</Directory> 

NameVirtualHost "my.server.on.port" 
Listen 80 

<VirtualHost *:80> 
    DocumentRoot "/var/www/html/QR/tst" 
    ServerName "my.server.on.port:80" 

    <Directory "/var/www/html/QR/tst"> 
      Options Indexes MultiViews FollowSymLinks 
      AllowOverride All 
      Order allow,deny 
      Allow from all 
    </Directory> 

    <Directory "/var/www/html/QR/tst/css/smoothness"> 
      Options Indexes MultiViews FollowSymLinks 
      AllowOverride All 
      Order allow,deny 
      Allow from all 
    </Directory> 
    <Directory "/var/www/html/QR/tst/development-bundle"> 
      Options Indexes MultiViews FollowSymLinks 
      AllowOverride All 
      Order allow,deny 
      Allow from all 
    </Directory> 
    <Directory "/var/www/html/QR/tst/development-bundle/ui"> 
      Options Indexes MultiViews FollowSymLinks 
      AllowOverride All 
      Order allow,deny 
      Allow from all 
    </Directory> 
    <Directory "/var/www/html/QR/tst/development-bundle/demos"> 
      Options Indexes MultiViews FollowSymLinks 
      AllowOverride All 
      Order allow,deny 
      Allow from all 
    </Directory> 

</VirtualHost> 

來自服務器的回覆是304.所有文件都有755 p ermission。沒有idia如何解決這個問題。感謝名單！

HTTP/1.1 304 Not Modified 
Date: Sat, 21 Jul 2012 08:45:38 GMT 
Server: Apache/2.2.22 (Fedora) 
Connection: close 
ETag: "c0744-f7a-4c553071e0d4e" 

這是錯誤的警報：

Answer 1

這對我的作品（在Chrome和IE測試）：

var request = $.ajax({ 
    type: "post", 
    url: "mmm.php", 
    data:"abcdefghijklmnopqrstuvwxyz", 
    success:function(data){ alert("success: " +JSON.stringify(data)); }, 
    error:function(data){ alert("error "+JSON.stringify(data)); }, 
    statusCode:{ 
      200:function(){alert("200 OK");}, 
      304:function(){alert("304 Not Modified");}, 
      404:function(){alert("404 No Found");}}, 
    isModified:function(){alert("Something was modified");} 
}); 

感謝任何幫助過的人！

Answer 2

試試這個Ajax請求

var request = $.ajax({ 
type:"post", 
url:"http://my.server.on.port/mmm.php", 
data:"abc=abcd", 
//success:function(data){ console.log("success "+data); }, 
//error:function(data){console.error("error "+data;}, 
statusCode:{ 
200:function(){console.log("got 200")}, 
304:function(){console.log("got 304")}, 
404:function(){console.error("got 404")}}, 
isModified:function(){console.log("Something was modified");} 
}).responseText; 
// i haven't used .done .fail but i believe the code below would work. 
request.done(function(data){ console.log("got response "+data); }); 
request.fail(function(jqXHR,textStatus){ 
console.log("Request Failed\n"+"object dump :"+console.log(jqXHR)+"\n"+"textStatus :"+textStatus); 
}); // changed according to the example from jquery site.