如何解決nonetype對象在Python中沒有屬性編碼錯誤2.7

Question

我運行下面的代碼：

from __future__ import unicode_literals 
import xml.etree.ElementTree as ET 
tree = ET.parse('dblp_16.xml') 
root = tree.getroot() 
f = open('hi', 'w') 
for country in root.findall('article'): 
    rank = country.find('year').text 
    name = country.find('title') 

    if(int(rank)>2009): 
     f.write(name.text.encode('utf8')) 
     f.write(':') 
     auth = country.findall('author') 
     for a in auth: 
      #print str(a) 
      f.write(a.text.encode('utf8')) 
      f.write(',') 
     f.write('\n') 

錯誤，同時運行上面的代碼發生：「nonetype對象沒有屬性編碼」。如何解決它？

Answer 1

只需選中if name.text is not None

from __future__ import unicode_literals 
import xml.etree.ElementTree as ET 
tree = ET.parse('dblp_16.xml') 
root = tree.getroot() 
f = open('hi', 'w') 
for country in root.findall('article'): 
    rank = country.find('year').text 
    name = country.find('title') 
    if not name.text: 
     continue 
    if(int(rank)>2009): 
     f.write(name.text.encode('utf8')) 
     f.write(':') 
     auth = country.findall('author') 
     for a in auth: 
      #print str(a) 
      f.write(a.text.encode('utf8')) 
      f.write(',') 
     f.write('\n')