Bean驗證約束（S）違反：「prePersist」

Question

我想用來存儲birthdate所以我在MySQL的選擇date，當我以我的數據庫中創建我的實體，事實證明這樣的：

import java.util.Date; 

    // ..code 
    @NotNull(message="fill you birthdate") 
    @Temporal(TemporalType.DATE) 
    private Date birthdate; 

但是當我嘗試堅持它給了我這個錯誤：

Bean Validation constraint(s) violated while executing Automatic Bean Validation on callback event:'prePersist'. Please refer to embedded ConstraintViolations for details.

什麼我錯在這裏做什麼？ 我正在閱讀一些關於谷歌定義時區的內容，我來自巴西，我應該怎麼做？

編輯

package entity; 

import java.io.Serializable; 
import javax.persistence.*; 
import javax.validation.constraints.NotNull; 
import javax.validation.constraints.Size; 

import org.hibernate.validator.constraints.Email; 

import java.util.Date; 
import java.util.List; 


/** 
* The persistent class for the user database table. 
* 
*/ 
@Entity 
public class User implements Serializable { 
    private static final long serialVersionUID = 1L; 

    @Id 
    @GeneratedValue(strategy=GenerationType.IDENTITY) 
    private Integer id; 

    @Temporal(TemporalType.DATE) 
    private Date birthdate; 

    @NotNull(message="informe seu e-mail") 
    @Email(message="e-mail inválido") 
    private String email; 

    @NotNull(message="informe seu gênero") 
    private String gender; 

    private String image; 

    @NotNull(message="informe seu nome completo") 
    private String name; 

    @Size(min=6,max=16, message="senha com no mínimo: 6 dígitos e no máximo 16 dígitos") 
    @NotNull(message="informe sua senha") 
    private String password; 

    //bi-directional many-to-one association to Document 
    @OneToMany(mappedBy="user") 
    private List<Document> documents; 

    //bi-directional many-to-one association to QuestionQuery 
    @OneToMany(mappedBy="user") 
    private List<QuestionQuery> questionQueries; 

    //bi-directional many-to-one association to Team 
    @OneToMany(mappedBy="user") 
    private List<Team> teams; 

    public User() { 
    } 

    public Integer getId() { 
     return this.id; 
    } 

    public void setId(Integer id) { 
     this.id = id; 
    } 

    public Date getBirthdate() { 
     return this.birthdate; 
    } 

    public void setBirthdate(Date birthdate) { 
     this.birthdate = birthdate; 
    } 

    public String getEmail() { 
     return this.email; 
    } 

    public void setEmail(String email) { 
     this.email = email; 
    } 

    public String getGender() { 
     return this.gender; 
    } 

    public void setGender(String gender) { 
     this.gender = gender; 
    } 

    public String getImage() { 
     return this.image; 
    } 

    public void setImage(String image) { 
     this.image = image; 
    } 

    public String getName() { 
     return this.name; 
    } 

    public void setName(String name) { 
     this.name = name; 
    } 

    public String getPassword() { 
     return this.password; 
    } 

    public void setPassword(String password) { 
     this.password = password; 
    } 

    public List<Document> getDocuments() { 
     return this.documents; 
    } 

    public void setDocuments(List<Document> documents) { 
     this.documents = documents; 
    } 

    public List<QuestionQuery> getQuestionQueries() { 
     return this.questionQueries; 
    } 

    public void setQuestionQueries(List<QuestionQuery> questionQueries) { 
     this.questionQueries = questionQueries; 
    } 

    public List<Team> getTeams() { 
     return this.teams; 
    } 

    public void setTeams(List<Team> teams) { 
     this.teams = teams; 
    } 

    public void print() { 
     System.out.println("User [id=" + id + ", birthdate=" + birthdate + ", email=" 
       + email + ", gender=" + gender + ", image=" + image + ", name=" 
       + name + ", password=" + password + "]"); 
    } 



} 

Answer 1

我做了什麼來解決我的問題是顛倒順序@Size和@NotNull

前：

@Size(min=6,max=16, message="senha com no mínimo: 6 dígitos e no máximo 16 dígitos") 
@NotNull(message="informe sua senha") 
private String password; 

後：

@NotNull(message="informe sua senha") 
@Size(min=6,max=16, message="senha com no mínimo: 6 dígitos e no máximo 16 dígitos") 
private String password; 

我不知道爲什麼會這樣才能事這麼多，但它=] 謝謝大家！

Answer 2

錯誤顯示您正試圖堅持實體未能 數據庫約束，所以嘗試確定要插入的確切值到數據庫中，你居然插入之前。

並嘗試通過評論/省略@NotNull註釋。

Answer 3

我得到了同樣的問題，但經過尋找答案小時，終於讓我找到它....您應該編輯您的AbstractFacade.java類，並添加以下代碼

public void create(T entity) { 

    ValidatorFactory factory = Validation.buildDefaultValidatorFactory(); 
    Validator validator = factory.getValidator(); 
    Set<ConstraintViolation<T>> constraintViolations = validator.validate(entity); 
    if(constraintViolations.size() > 0){ 
     Iterator<ConstraintViolation<T>> iterator = constraintViolations.iterator(); 
     while(iterator.hasNext()){ 
      ConstraintViolation<T> cv = iterator.next(); 
      System.err.println(cv.getRootBeanClass().getName()+"."+cv.getPropertyPath() + " " +cv.getMessage()); 

      JsfUtil.addErrorMessage(cv.getRootBeanClass().getSimpleName()+"."+cv.getPropertyPath() + " " +cv.getMessage()); 
     } 
    }else{ 
     getEntityManager().persist(entity); 
    } 
} 

現在此方法會提醒您哪些屬性以及驗證失敗的原因。 我希望這對你有用，就像它對我一樣。

Answer 4

當然，Iomanip的回答是完全正確的！我只是稍微擴展了一下。也許這也有幫助：

private boolean constraintValidationsDetected(T entity) { 
    ValidatorFactory factory = Validation.buildDefaultValidatorFactory(); 
    Validator validator = factory.getValidator(); 
    Set<ConstraintViolation<T>> constraintViolations = validator.validate(entity); 
    if (constraintViolations.size() > 0) { 
     Iterator<ConstraintViolation<T>> iterator = constraintViolations.iterator(); 
     while (iterator.hasNext()) { 
     ConstraintViolation<T> cv = iterator.next(); 
     System.err.println(cv.getRootBeanClass().getName() + "." + cv.getPropertyPath() + " " + cv.getMessage()); 

     JsfUtil.addErrorMessage(cv.getRootBeanClass().getSimpleName() + "." + cv.getPropertyPath() + " " + cv.getMessage()); 
     } 
     return true; 
    } 
    else { 
     return false; 
    } 
    } 

    public void create(T entity) { 
    if (!constraintValidationsDetected(entity)) { 
     getEntityManager().persist(entity); 
    } 
    } 

    public T edit(T entity) { 
    if (!constraintValidationsDetected(entity)) { 
     return getEntityManager().merge(entity); 
    } 
    else { 
     return entity; 
    } 
    } 

    public void remove(T entity) { 
    if (!constraintValidationsDetected(entity)) { 
     getEntityManager().remove(getEntityManager().merge(entity)); 
    } 
    } 

Answer 5

當我試圖堅持一個實體時，我花了幾個小時掙扎着這個錯誤。

Bean Validation constraint(s) violated while executing Automatic Bean Validation on callback event:'preUpdate'. Please refer to embedded ConstraintViolations for details. 

此錯誤消息沒有幫助，相當混亂...

反正在我的情況下，錯誤的原因是 - 在Enity

@Size(min = 1, max = 10) 
@Column(name = Utilizator.JPA_DISCRIMINATOR) 
private String jpaDiscriminator; 

和數據庫列定義註釋之間的差異：

jpaDiscriminator VARCHAR（15）NOT NULL，

Answer 6

我有類似的問題。在我的情況下，參考PK和FK的大小不同（見示例）。

實體A：實體B

實體B的

some_pk INTEGER NOT NULL, 
fk_b  VARCHAR2(5 CHAR) 
... 

fk_b引用ID字段：

id VARCHAR2(4 CHAR) 
... 

ID是這裏PK。

注ID（）和FK_B的尺寸（）。將B的ID更改爲5 CHAR錯誤消失。

Answer 7

我得到了一個快捷方式，抓住以下異常，你堅持的實體。在我的情況下，它在EJB添加方法。我在哪裏做em.persist()。然後檢查服務器日誌，您將看到哪些屬性約束違規。

catch (ConstraintViolationException e) { 
     log.log(Level.SEVERE,"Exception: "); 
     e.getConstraintViolations().forEach(err->log.log(Level.SEVERE,err.toString())); 
    }