排序包含字符串，日期和數字的數組

Question

var myArray = [ 
    '_aaaa_2013-09-25_ssss9.txt', 
    '_aaaa_2013-09-25_ssss8.txt', 
    '_aaaa_2013-09-26_ssss1.txt', 
    '_aaaa_2013-09-25_ssss10.txt', 
    '_aaaa_2013-09-26_ssss2.txt', 
    '_aaaa_2013-09-25_ssss13.txt', 
    '_aaaa_2013-09-25_ssss5.txt', 
    '_aaaa_2013-09-25_ssss6.txt', 
    '_aaaa_2013-09-25_ssss7.txt' 
]; 

我需要按日期和數字對數組進行排序。

結果應該是

var result = [ 
    '_aaaa_2013-09-25_ssss5.txt', 
    '_aaaa_2013-09-25_ssss6.txt', 
    '_aaaa_2013-09-25_ssss7.txt', 
    '_aaaa_2013-09-25_ssss8.txt', 
    '_aaaa_2013-09-25_ssss9.txt', 
    '_aaaa_2013-09-25_ssss13.txt', 
    '_aaaa_2013-09-26_ssss1.txt', 
    '_aaaa_2013-09-26_ssss2.txt' 
]; 

我曾嘗試以下代碼。此將僅日期，進行排序，但我需要的是之前」我.txt'.How可以做到這一點的數量進行排序。

myArray.sort(function (a, b) { 

    var timeStamp1 = a.substring(a.indexOf('_aaaa') + 6, a.indexOf('_ssss')); 
    var timeStamp2 = b.substring(b.indexOf('_aaaa') + 6, b.indexOf('_ssss')); 
    timeStamp1 = new Date(Date.UTC(timeStamp1[0], timeStamp1[1], timeStamp1[2])); 
    timeStamp2 = new Date(Date.UTC(timeStamp2[0], timeStamp2[1], timeStamp2[2])); 

    return (timeStamp1 > timeStamp2) ? 1 : (timeStamp2 > timeStamp1 ? -1 : 0); 

}); 

Answer 1

你可以做這樣的：

var re = /^_aaaa_(\d\d\d\d-\d\d-\d\d)_ssss(\d+)\.txt$/; 

var result = myArray.slice().sort(function(a, b) { 
    var aa = a.match(re), bb = b.match(re); 
    return(
     aa[1] < bb[1] ? -1 : 
     aa[1] > bb[1] ? 1 : 
     aa[2] - bb[2] 
    ); 
}); 

注意使用.slice()創建數組的一個副本。如果您想對原始數組進行排序，則可以省略此項。 （感謝@DerFlatulator提醒！）

Answer 2

這對我有效。

myArray.sort(function (a, b) { 
    var a_s = a.substring(0, a.indexOf('ssss') + 4); 
    var a_n = a.substring(a.indexOf('ssss') + 4, a.indexOf('.txt')); 
    var b_s = b.substring(0, b.indexOf('ssss') + 4); 
    var b_n = b.substring(b.indexOf('ssss') + 4, b.indexOf('.txt')); 
    if (a_s < b_s) 
     return -1; 
    if (a_s > b_s) 
     return 1; 
    return parseInt(a_n) - parseInt(b_n); 
}); 

jsFiddle

Answer 3

按字符串內的數字值排序。

這是假設：

• 數是整數
• 每個字符串是不同
• 日期可能會作爲數字排序（年，月，日）

["aa_123","aa_13","aa_2","aa_22_bb_23","aa_22_bb_3"].sort(function (a , b) {

var as = a.split(/([0-9]+)/); // splits string retaining separators 
    var bs = b.split(/([0-9]+)/); 
    var i,c = Math.min(as.length,bs.length); 
    for (i=0;i<c && as[i]===bs[i];++i) ; 
    var an = (i&1)?+as[i]:as[i]; // separators (digits) always at odd index 
    var bn = (i&1)?+bs[i]:bs[i]; 
    return (an<bn)?-1:1; // assumes every string different 

});

結果：

[ 
    "aa_2", 
    "aa_13", 
    "aa_22_bb_3", 
    "aa_22_bb_23", 
    "aa_123" 
] 

Answer 4

此，從給定串中提取的數字，並提出一個給定的重量上的每個數值的一部分。因此，您可以按照計數，日，月，年的優先順序對其進行排序。

function weightedNumSort(myArray,weightNum,weightString) {  
    var WEIGHTS_NUM = weightNum || [1,2,4,3]; //[YEAR,MONTH,DAY,COUNT], You can pass an array with appropriate weights for the number at the given position in the text, e.g year is the first Number 
    var WEIGHT_STRING = weightString || 1; //And a weight for the string value. If none get passed, default weights are used 

     function weightedSum (a,b,i) { 
      return (a + b * (WEIGHTS_NUM [i-1] || 1)); 
     } 

    myArray = myArray.slice().sort(function (a, b) { 
     var reg = /(\d+)/g //A regex to extract the numerical part 

     var lNum = a.match(reg) //Extract the numerical parts we now have an array ["2013","09","26","2"] 

     var rNum = b.match(reg) 

     var delta = Array.apply(null,{length:lNum.length+1}); 
      delta [0] = 0; //add a 0 at the beginning, for convenience with the reduce function 

     for (var i=0,j=lNum.length; i < j; i++) { 
      var value = lNum[i] - rNum[i]; 
      value = ~~ (value/Math.abs (value)) // 1 for positive values, 0 for 0 , -1 for negative values, to make weighting easier 
      delta[i+1] = value; 
     } 

     var weightedNumValue = delta.reduce (weightedSum) //Put a weight on the number parts. 
     var weightedStrValue = WEIGHT_STRING * (a > b ? 1 : a < b ? -1 : 0)  
     return weightedNumValue + weightedStrValue //Add the weighted values and we have a positive or negative value with a correct weight on the numerical parts 
    }) 
    return myArray 
} 

輸出

console.log (
    weightedNumSort (myArray)  
) /* 
[ 
    "_aaaa_2013-09-25_ssss5.txt", 
    "_aaaa_2013-09-25_ssss6.txt", 
    "_aaaa_2013-09-25_ssss7.txt", 
    "_aaaa_2013-09-25_ssss8.txt", 
    "_aaaa_2013-09-25_ssss9.txt", 
    "_aaaa_2013-09-25_ssss10.txt", 
    "_aaaa_2013-09-25_ssss13.txt", 
    "_aaaa_2013-09-26_ssss1.txt", 
    "_aaaa_2013-09-26_ssss2.txt" 
]*/ 

和Fiddle