搜索超過使用NSPredicate

Question

我的數據結構，在字典中的所有臺詞是：

現在我遍歷目錄，並添加「名稱」字符串NSMutableArray然後搜索並使用NSPredicate過濾器的數據。

如何搜索整個列表？通過名稱 & 地址所有數組中的字符串？

過濾數據：

- (void)filterContentForSearchText:(NSString*)searchText scope:(NSString*)scope 
{ 
    NSPredicate *resultPredicate = [NSPredicate 
            predicateWithFormat:@"SELF contains[cd] %@", 
            searchText]; 

    searchResults = [sectionsNames filteredArrayUsingPredicate:resultPredicate]; 
} 

加載數據：

#pragma mark - 
#pragma mark Load plist file 
- (void)loadPList 
{ 

    dispatch_async(dispatch_get_global_queue(DISPATCH_QUEUE_PRIORITY_DEFAULT, 0), ^{ 

     NSArray *documentPaths = NSSearchPathForDirectoriesInDomains(NSCachesDirectory, NSUserDomainMask, YES); 
     NSString *path = [[documentPaths lastObject] stringByAppendingPathComponent:@"data.plist"]; 
     NSDictionary *dict = [NSDictionary dictionaryWithContentsOfFile:path]; 

     NSMutableDictionary *resultDic = [[NSMutableDictionary alloc] init]; 
     NSMutableArray *resultArray = [[NSMutableArray alloc] init]; 
     NSMutableArray *resultName = [[NSMutableArray alloc] init]; 

     sectionKeys = [NSMutableArray new]; 
     sectionsTitle = [NSMutableArray new]; 
     sectionsNames = [NSMutableArray new]; 

     dispatch_async(dispatch_get_main_queue(), ^{ 


      NSMutableArray *annotations = [[NSMutableArray alloc]init]; 

      NSMutableArray *annotationsToRemove = [ mapView.annotations mutableCopy ] ; 
      [ annotationsToRemove removeObject:mapView.userLocation ] ; 
      [ mapView removeAnnotations:annotationsToRemove ] ; 

    ann = [dict objectForKey:@"Blue"]; 
       [resultArray addObject:@"Blue"]; 
       [resultDic setValue:ann forKey:@"Blue"]; 
       [sectionKeys addObject:@"Siwa"]; 


       for(int i = 0; i < [ann count]; i++) { 


        NSString *coordinates = [[ann objectAtIndex:i] objectForKey:@"Coordinates"]; 

        double realLatitude = [[[coordinates componentsSeparatedByString:@","] objectAtIndex:1] doubleValue]; 
        double realLongitude = [[[coordinates componentsSeparatedByString:@","] objectAtIndex:0] doubleValue]; 

        MyAnnotation *myAnnotation = [[MyAnnotation alloc] init]; 
        CLLocationCoordinate2D theCoordinate; 
        theCoordinate.latitude = realLatitude; 
        theCoordinate.longitude = realLongitude; 

        myAnnotation.coordinate=CLLocationCoordinate2DMake(realLatitude,realLongitude); 
        myAnnotation.title = [[ann objectAtIndex:i] objectForKey:@"Name"]; 
        myAnnotation.subtitle = [[ann objectAtIndex:i] objectForKey:@"Address"]; 
        myAnnotation.icon = [[ann objectAtIndex:0] objectForKey:@"Icon"]; 

        NSString *name = [[ann objectAtIndex:i] objectForKey:@"Name"]; 
        [resultName addObject:name]; 

        [mapView addAnnotation:myAnnotation]; 
        [annotations addObject:myAnnotation]; 


       } 

    self.tableData = resultDic; 
      self.sectionsTitle = resultArray; 
      self.sectionsNames = resultName; 

      [myTable reloadData]; 


     }); 



    }); 


} 

Answer 1

如果你的字典裏只包含數組，那麼你可以循環遍歷字典的鍵和單獨過濾每個（自由編寫的代碼）：

NSPredicate *resultPredicate = [NSPredicate 
           predicateWithFormat:@"Name CONTAINS[cd] %@ OR Address CONTAINS[cd] %@", 
           searchText, 
           searchText]; 

NSMutableArray *allMatches = [NSMutableArray array]; 

for (NSString *key in myDictionary) { 
    NSArray *array = [myDictionary objectForKey:key]; 

    NSArray *matches = [array filteredArrayUsingPredicate:resultPredicate]; 

    if (matches.count > 0) { 
     [allMatches addObjectsFromArray:matches]; 
    } 
} 

這樣做，您還可以訪問原始密鑰，如果您需要d it。並且你完成了所有匹配的列表（一組匹配的字典）。

現在在您的表格視圖中，您可以返回所有匹配計數的行數，並從字典中獲取Name和Address以顯示。