無法打印多維數組

我的需求是訪問json響應，將其存儲在php變量中，以便我將這些變量插入到數據庫中。這裏是我的代碼無法打印多維數組

$jsondata = file_get_contents('dealdetails.json'); 
$array = json_decode($jsondata, true); 
$arrlength = count($array); 
echo $arrlength; 

for ($x = 0; $x < $arrlength; $x++) 
{ 
    //echo $x; 
    $PromoID = $array[$x]['PromoID']; 
    $OfferID = $array[$x]['OfferID']; 
    $OfferName = $array[$x]['OfferName']; 
    $Type = $array[$x]['Type']; 
    $Code = $array[$x]['Code']; 
    $Title = $array[$x]['Title']; 
    $Description = $array[$x]['Description']; 
    $Category = $array[$x]['Category']; 
    $OfferPage = $array[$x]['OfferPage']; 
    $DateAdded = $array[$x]['DateAdded']; 
    $Expiry = $array[$x]['Expiry']; 

    echo "<br>"; 
}

無法在迭代

例獲得分配的值： $數組[0] [ 'promoId']正在凡爲$陣列[$ X] [ 'promoId' ] 不管用。

的Json樣品要求：

[{"featured":"0","exclusive":"1","promo_id":"xxx","offer_id":"x","offer_name":"xxx","coupon_title":"xx","category":"","coupon_description":"","coupon_type":"Coupon","coupon_code":"xxx","ref_id":"xxx","link":"xxx","coupon_expiry":"2017-03-31","added":"2016-01-05","preview_url":"http:\/\/www.stalkbuylove.com\/","store_link":"http:\/\/tracking.vcommission.com\/aff_c?offer_id=230&aff_id=43367"}, 
[{"featured":"0","exclusive":"1","promo_id":"xxx","offer_id":"x","offer_name":"xxx","coupon_title":"xx","category":"","coupon_description":"","coupon_type":"Coupon","coupon_code":"xxx","ref_id":"xxx","link":"xxx","coupon_expiry":"2017-03-31","added":"2016-01-05","preview_url":"http:\/\/www.stalkbuylove.com\/","store_link":"http:\/\/tracking.vcommission.com\/aff_c?offer_id=230&aff_id=43367"},

請建議。

來源

2016-07-11 user3762051

真的很難理解你的問題，請重新說明。 –

@OfirBaruch：對不起，造成的不便。改編問題請建議 – user3762051

$ array [x]將是$ array [$ x]，$ x的值甚至不是'$ x' – developerCK

嘗試這樣：

$jsondata = file_get_contents('dealdetails.json'); 
$array = json_decode($jsondata, true); 

foreach ($array as $key => $value) 
{ 
    //print_r($value); 

    echo $value['PromoID']; 
    $PromoID = $value['PromoID']; 
    $OfferID = $value['OfferID']; 
    $OfferName = $value['OfferName']; 
    $Type = $value['Type']; 
    $Code = $value['Code']; 
    $Title = $value['Title']; 
    $Description = $value['Description']; 
    $Category = $value['Category']; 
    $OfferPage = $value['OfferPage']; 
    $DateAdded = $value['DateAdded']; 
    $Expiry = $value['Expiry']; 

    echo "<br>"; 
}

使用foreach()是通過數組迭代的正確方法。

另請注意，您提供的示例JSON使用promo_id而不是PromoID，因此您需要$value['promo_id']。

來源

2016-07-11 06:58:18 Will

感謝您的幫助。它的工作現在。 – user3762051

沒問題，樂於幫忙！ :) – Will

會有一些小的幫助。實際上，我現在使用的json文件實際上是Web服務調用的輸出。我可以直接使用該Web服務響應而不是複製到文件然後使用它？ – user3762051

無法打印多維數組

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