獲取電子郵件imap_fetchbody（）的身體

Question

如何獲取電子郵件的身體..

有了這個例子中只有約25％的所有電子郵件體被取出！？

$structure = imap_fetchstructure($this->stream, $header->msgno); 

if(!empty($structure->parts[1])){ 
    $message = imap_fetchbody($this->stream, $header->msgno, '1'); 

    switch($structure->parts[1]->encoding){ 
     case 1: 
      $message = imap_8bit($message); 
      break; 

     case 3: 
      $message = imap_base64($message); 
      break; 

     case 4: 
      $message = imap_qprint($message); 
      break; 
    } 

    echo $message; 
} 

更新

// gets 35 of 131 
$message = imap_fetchbody($this->stream, $header->msgno, '1'); 

// gets 10 of 131 
$message = imap_fetchbody($this->stream, $header->msgno, '1.2'); 

Answer 1

找到了解決辦法：d

public function parse_mail($header){ 
    $structure = imap_fetchstructure($this->stream, $header->msgno); 

    if(isset($structure->parts)){ 
     $parse = $this->parse_parts($structure->parts, $header->msgno); 
    } 
    else{ 
     $parse = $this->parse_parts($structure, $header->msgno); 
    } 

    if($parse){ 
     print_r($parse); 
    } 
} 

private function parse_parts($parts, $msgno){ 
    $message = imap_fetchbody($this->stream, $msgno, '1'); 

    if(!empty($parts->encoding)){ 
     switch($parts->encoding){ 
      /*case 1: 
       $message = imap_8bit($message); 
       break;*/ 

      case 3: 
       $message = imap_base64($message); 
       break; 

      case 4: 
       $message = imap_qprint($message); 
       break; 
     } 
    } 

    return $message; 
}