在java中獲取mp3音頻信號作爲數組

Question

我一直在嘗試獲取MP3音頻流作爲浮點數組。我已經得到了下面的示例代碼的數組。我不確定我是否可以使用這個數組來應用FFT。因爲這個數組與我從C++的使用LAME的代碼中獲得的數組不匹配[或類似]。

import java.io.File; 
import java.io.IOException; 
import java.io.PrintStream; 

import javax.sound.sampled.AudioFormat; 
import javax.sound.sampled.AudioInputStream; 
import javax.sound.sampled.AudioSystem; 
import javax.sound.sampled.DataLine; 
import javax.sound.sampled.LineUnavailableException; 
import javax.sound.sampled.SourceDataLine; 
import javax.sound.sampled.UnsupportedAudioFileException; 

import javazoom.spi.mpeg.sampled.file.MpegAudioFileReader; 

import org.tritonus.share.sampled.FloatSampleTools; 



public class onjava { 



    public static void main(String[] args) { 
     try { 

     File file = new File("mymp3file.mp3"); 
     MpegAudioFileReader mpegAudioFileReader = new MpegAudioFileReader(); 
     int fl = mpegAudioFileReader.getAudioFileFormat(file).getFrameLength(); 
     System.out.println(fl); 
     AudioInputStream in= AudioSystem.getAudioInputStream(file); 
     AudioInputStream din = null; 
     AudioFormat baseFormat = in.getFormat(); 
     onjava oj = new onjava(); 
     AudioFormat decodedFormat = 
      new AudioFormat(AudioFormat.Encoding.PCM_SIGNED, 
          baseFormat.getSampleRate(), 
          16, 
          baseFormat.getChannels(), 
          baseFormat.getChannels() * 2, 
          baseFormat.getSampleRate(), 
          false); 
     int len = (int)file.length(); 
     din = AudioSystem.getAudioInputStream(decodedFormat, in); 

     oj.rawplay(decodedFormat, din, len, fl); 
      in.close(); 
     } catch (IOException e) { 
      e.printStackTrace(); 
     } catch (LineUnavailableException e) { 
      e.printStackTrace(); 
     } catch (UnsupportedAudioFileException e) { 
      // TODO Auto-generated catch block 
      e.printStackTrace(); 
     } 

    } 
    private void rawplay(AudioFormat targetFormat, AudioInputStream din , int len, int frameLength) 
      throws IOException, LineUnavailableException { 
     byte[] data = new byte[len-1]; 
     float[] floatArray = new float[len-1]; 
     SourceDataLine line = getLine(targetFormat); 
     File textFile = new File("outputfile.txt"); 
     PrintStream printStream = new PrintStream(textFile); 
     System.setOut(printStream); 

     if (line != null) { 
      // Start 
      line.start(); 
      int nBytesRead = 0, nBytesWritten = 0; 
      while (nBytesRead != -1) { 
       nBytesRead = din.read(data, 0, 8000); 
       if (nBytesRead != -1) { 
       //Please tell me if something is wrong with the arguments passed below 
        FloatSampleTools.byte2floatGeneric(data, 0, targetFormat.getFrameSize(), floatArray, 0, 1000, targetFormat); 

        for (int i = 0; i < nBytesRead; i++) { 
         if(floatArray[i] != 0.0) 
         System.out.println(floatArray[i]); 
        } 

       } 
      } 
      // Stop 
      line.drain(); 
      line.stop(); 
      line.close(); 
      din.close(); 
     } 


    } 


    private SourceDataLine getLine(AudioFormat audioFormat) 
      throws LineUnavailableException { 
     SourceDataLine res = null; 
     DataLine.Info info = new DataLine.Info(SourceDataLine.class, 
       audioFormat); 
     res = (SourceDataLine) AudioSystem.getLine(info); 
     res.open(audioFormat); 
     return res; 
    } 

} 

如果在上面的代碼中有任何錯誤，請提出建議。此外，如果任何其他純Java API可用於處理MP3文件。我需要mp3音頻流中的數組。

如果可以的話，還請告訴我有關LAME的純Java實現。

謝謝！

Answer 1

javazoom.spi.mpeg.sampled.file.MpegAudioFileReader 

&

org.tritonus.share.sampled.FloatSampleTools 

都沒有發現。指定您用於這些功能的庫。