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我創建一個WordPress插件,現在我得到這樣的錯誤錯誤使用時執行opendir顯示()
Warning: opendir(http://localhost/wordpress/wp-content/uploads/): failed to open dir: not implemented in http://localhost/wordpress/wp-content/plugins/my-plugin/FlxZipArchive.php on line 37
Warning: readdir() expects parameter 1 to be resource, boolean given in http://localhost/wordpress/wp-content/plugins/my-plugin/FlxZipArchive.php on line 38
而這些文件
的index.php
<?php
$upload_dir = wp_upload_dir();
$folder_name = $upload_dir['baseurl'];
//Don't forget to remove the trailing slash
$the_folder =$foldername;
$zip_file_name = WP_CONTENT_DIR."/".'uploads.zip';
$za = new FlxZipArchive;
$res = $za->open($zip_file_name, ZipArchive::CREATE);
if($res === TRUE) {
$za->addDir($the_folder, basename($the_folder));
$za->close();
}
else
echo 'Could not create a zip archive';
?>
FlxZipArchive .php
<?
/**
* FlxZipArchive, Extends ZipArchiv.
* Add Dirs with Files and Subdirs.
*
* <code>
* $archive = new FlxZipArchive;
* // .....
* $archive->addDir('test/blub', 'blub');
* </code>
*/
class FlxZipArchive extends ZipArchive {
/**
* Add a Dir with Files and Subdirs to the archive
*
* @param string $location Real Location
* @param string $name Name in Archive
* @author Nicolas Heimann
* @access private
**/
public function addDir($location, $name) {
$this->addEmptyDir($name);
$this->addDirDo($location, $name);
} // EO addDir;
/**
* Add Files & Dirs to archive.
*
* @param string $location Real Location
* @param string $name Name in Archive
* @author Nicolas Heimann
* @access private
**/
private function addDirDo($location, $name) {
$name .= '/';
$location .= '/';
// Read all Files in Dir
$dir = opendir ($location);
while ($file = readdir($dir))
{
if ($file == '.' || $file == '..') continue;
// Rekursiv, If dir: FlxZipArchive::addDir(), else ::File();
$do = (filetype($location . $file) == 'dir') ? 'addDir' : 'addFile';
$this->$do($location . $file, $name . $file);
}
} // EO addDirDo();
}
?>
執行的index.php它只是創造與一個空文件夾中的zip文件,並退出時每次
請別人幫我解決這個錯誤
所以我應該用什麼執行opendir的insted的()有效PARAM? –
我不確定你想要在這裏實現什麼。我想你想訪問本地目錄,對不對?如果是這樣,比正確的問題是什麼是正確的參數。您應該將常規路徑傳遞到目錄,而不是將URL傳遞給'opendir'函數。就這樣。 –
謝謝你的作品! –