你如何計算用戶輸入的整數的均值可以被數字整除？

Question

到目前爲止..我這個編碼：

While True: 
    div_5 = [] 
    x = float(input("Please input an integer(negative if you want to stop: ")) 
    x = int(x) 
    length = len(div_5) 
    total_sum = sum(div_5) 
    average = total_sum/length 
    if x % 5: 
     div_5.append(x) 
    if x < 0: 
     break 
print(average) 

當我運行的代碼，它說，7號線有ZeroDivisionError。我究竟做錯了什麼？我添加了x，如果它能被列表5整除，爲什麼這麼說？ 任何提示將有助於我是新的python。

這是我需要做的

我一直在這一個星期，小時的時間。我似乎無法弄清楚它的正確性。

Answer 1

nums = [] 
while True: 
    x = int(input("Please input an integer(negative if you want to stop: ")) 

    if x < 0: 
     div_5 = [x for x in nums if x % 5 == 0] 
     try: 
      print(sum(div_5)/float(len(div_5))) 
     except ZeroDivisionError: 
      print("No number divisible by 5") 
     break 

    nums.append(x) 

事實上，你不需要保留不能被5整除的數字。下面是一個忽略零的運行平均值的方法。

count = 0. 
average = 0. 
while True: 
    x = int(input("Please input a positive integer(negative if you want to stop: ")) 

    if x < 0: 
     print(average) 
     break 
    if x % 5 == 0 and x != 0: 
     count += 1 
     average = average * (count - 1)/count + (1./count) * x 

Answer 2

你可以暗示從這個代碼，但因爲這似乎是一個學校的功課，所以我建議你應該嘗試自己，如果你想提高你的編碼。

user_input=[] 
while True: 

    x = int(input("Please input an integer(negative if you want to stop: ")) 
    if x>0: 
     user_input.append(x) 
    else: 
     break 

div_5=[item for item in user_input if item%5==0] 
print('The mean is {}'.format(sum(div_5)/len(div_5))) 

輸出：

Please input an integer(negative if you want to stop: 1 
Please input an integer(negative if you want to stop: 2 
Please input an integer(negative if you want to stop: 3 
Please input an integer(negative if you want to stop: 4 
Please input an integer(negative if you want to stop: 5 
Please input an integer(negative if you want to stop: 6 
Please input an integer(negative if you want to stop: 7 
Please input an integer(negative if you want to stop: 8 
Please input an integer(negative if you want to stop: 9 
Please input an integer(negative if you want to stop: 15 
Please input an integer(negative if you want to stop: -12 
The mean is 10.0 

Answer 3

正如我在評論中說：

1. 您需要while循環開始之前創建div_5列表。
2. 你應該讀取整數輸入，所以float調用是無用的。
3. 如果x在讀取後立即爲負數，則測試它。
4. 在跳出循環之前不要計算平均值，並且如果列表中沒有數據，則不計算平均值。

而且，你的可分性測試是倒退：x % 5是零，如果x是5整除，而零被認爲是假。

下面是您的代碼的修復版本。

div_5 = [] 
while True: 
    x = int(input("Please input an integer (negative if you want to stop): ")) 
    if x < 0: 
     break 
    if x % 5 == 0: 
     div_5.append(x) 

if div_5: 
    average = sum(div_5)/len(div_5) 
else: 
    average = 0 
print(average) 

演示

Please input an integer (negative if you want to stop): 1 
Please input an integer (negative if you want to stop): 5 
Please input an integer (negative if you want to stop): 6 
Please input an integer (negative if you want to stop): 10 
Please input an integer (negative if you want to stop): -4 
7.5 

當我們跳出主循環測試if div_5測試是否有在div_5列表中的任何號碼，只要有執行部門。如果列表中沒有數字，則平均值爲零。