使用陣列

Question

我有公司名稱的數組插入多個MySQL記錄，我插入每個公司名稱作爲單獨record.below是代碼

<input type="text" name="company_name[]"> 

$company_name = $_POST['company_name']; 

if($company_name) 
{ 
    foreach($company_name as $company) 
    { 
    $mycompany[] = $company; 
    } 
} 

$val="('".implode("'), ('",$mycompany)."')"; 
$sql = "INSERT INTO `table` 
(`company_name`) VALUES ".$val.""; 

上面的查詢看起來像這樣，它成功地插入2個記錄在表。

INSERT INTO `table` (`company_name`) VALUES ('DELL'), ('IBM') 

現在的問題是，每COMPANY_NAME有一個company_code，我想每個記錄插入和有第三值可以假設order_num這也是我想插入但order_num應該在所有記錄相同，我需要以下

INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','DELL','axc89'), ('123','IBM','bxc90') 

Answer 1

好吧，你最後努力生產出可以理解的

1）本該代碼是絕對沒用：

$company_name = $_POST['company_name']; 

if($company_name) 
{ 
    foreach($company_name as $company) 
    { 
    $mycompany[] = $company; 
    } 
} 

爲$ myCompany的是一個確切的$ COMPANY_NAME

重複2）爲了得到你的「非常複雜」的查詢

foreach($_POST['company_name'] as $key => $value) 
{ 
    $name = mysql_real_escape_string($value); 
    $code = mysql_real_escape_string($_POST['company_code'][$key]); 
    $mycompany[] = "(123,'$name','$code')"; 
} 
$sql = "INSERT INTO `table` (order_num,company_name,company_code) VALUES "; 
$sql .= implode(",",$mycompany); 

Answer 2

INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','DELL','axc89'); 
INSERT INTO `table` (`order_num`,`company_name`,`company_code`) VALUES ('123','IBM','bxc90'); 

查詢可以使用數組

$arrray_to_be_inserted=array 
(
    [0]=>array('123','DELL','axc89'), 
    [1]=>array('123','IBM','bxc90') 
); 

Answer 3

不是傳遞價值在的foreach一個新的變量，嘗試訪問爲$鍵和$值，試試這個，看看它是否能幫助你

<?php 

$company_name = array("DEL","IBM"); 
$company_code = array("1","2"); 
$order_num = array("4","5"); 

if($company_name) 
{ 
foreach($company_name as $key => $value) 
{ 
    $mycompany[] = $value; 
    $mycompanycode[] = $company_code[$key]; 
    $myordernum[] = $order_num[$key]; 
} 
} 

？>

只要確保名字和他們的值相互對應。