如何分割文本的長字符串使用bash

Question

我有一個包含我的日誌信息爲文件：

Sat May 20 00:34:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers Sat May 20 00:35:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers Sat May 20 00:36:04 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 

我想，所以它看起來像這樣拆分此日誌數據轉換線：

Sat May 20 00:34:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 
Sat May 20 00:35:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 
Sat May 20 00:36:04 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 

任何想法？

Answer 1

嘗試：

perl -i.bkp -pe 's/containers/containers\n/' file.log 

這個假定字containers是應該是什麼在每行

Answer 2

結束使用sed：

$ sed 's/containers */containers\n/g' file 
Sat May 20 00:34:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 
Sat May 20 00:35:03 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 
Sat May 20 00:36:04 EST 2017 -- lane3a 4 0 -- lane3b 5 4 9 Total active sales: 4 Total bidders in sales: -- caster3a 0 -- caster3b 0 0 Total A/V 0 Estimated containers 

或：

$ sed 's/\(containers\) */\1\n/g' file 

Answer 3

你可以閱讀整個文件到一個猛砸變量和使用參數擴展containers通過換行後更換空間：

text=$(< infile) 
echo "${text//containers /containers$'\n'}"