For循環與子字符串

在這裏開始CS學生，試圖獲得循環處理。我的任務是採取一個字符串s，如果s = 'abcd'，程序將打印：'a,b,c,d,ab,bc,cd,abc,bcd,abcd'。顯然begin索引和end索引更改爲循環迭代 - (0,1),(1,2),(2,3),(3,4)。這很好，我可以打印：'a,b,c,d'。但是，我如何控制它，使之從(0,2),(1,3),(2,4)開始，然後是(0,3),(1,4),，最後是(0,4)？這是我難過的地方。感謝您的幫助，這裏是我的代碼：For循環與子字符串

void printSubstring() 
{ 
    int len = s.length(); 

    for (int i=0;i<len;i++) 
    { 
     for (int k=0;k<len;k++) 
      System.out.print(s.substring(k,k+1)+", "); 
    } 
    System.out.println(); 
}

來源

2013-10-23 CSpadawan

您的唯一要求的定義是在您的前兩句話。通過該定義，以下就足夠了：'if（s.equals（「abcd」））{return「a，b，c，d，ab，bc，cd，abc，bcd，abcd」;} return「」; '//否則沒有定義，這裏任何東西都是有效的。 – Cruncher

s可以是任何字符串。 – CSpadawan

這裏有一個提示：你有兩個循環，兩個計數器......'我'和'K'。你在哪裏使用'我'？ – tredontho

for (int i=0;i<len;i++) 
{ 
    for (int k=0;k<len-i;k++) 
     System.out.print(s.substring(k,k+i+1)+","); 
}

這是您的結構應該工作。

在每一步內循環中，要打印的字符串數減少（使用-i）。和琴絃的長度增加（使用+ i的子串）

測試用：abcdefghijklmnopqrstuvwxyz

輸出：

a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,ab,bc,cd,de,ef,fg,gh,hi,ij,jk,kl,lm,mn,no,op,pq,qr,rs,st,tu,uv,vw,wx,xy,yz,abc,bcd,cde,def,efg,fgh,ghi,hij,ijk,jkl,klm,lmn,mno,nop,opq,pqr,qrs,rst,stu,tuv,uvw,vwx,wxy,xyz,abcd,bcde,cdef,defg,efgh,fghi,ghij,hijk,ijkl,jklm,klmn,lmno,mnop,nopq,opqr,pqrs,qrst,rstu,stuv,tuvw,uvwx,vwxy,wxyz,abcde,bcdef,cdefg,defgh,efghi,fghij,ghijk,hijkl,ijklm,jklmn,klmno,lmnop,mnopq,nopqr,opqrs,pqrst,qrstu,rstuv,stuvw,tuvwx,uvwxy,vwxyz,abcdef,bcdefg,cdefgh,defghi,efghij,fghijk,ghijkl,hijklm,ijklmn,jklmno,klmnop,lmnopq,mnopqr,nopqrs,opqrst,pqrstu,qrstuv,rstuvw,stuvwx,tuvwxy,uvwxyz,abcdefg,bcdefgh,cdefghi,defghij,efghijk,fghijkl,ghijklm,hijklmn,ijklmno,jklmnop,klmnopq,lmnopqr,mnopqrs,nopqrst,opqrstu,pqrstuv,qrstuvw,rstuvwx,stuvwxy,tuvwxyz,abcdefgh,bcdefghi,cdefghij,defghijk,efghijkl,fghijklm,ghijklmn,hijklmno,ijklmnop,jklmnopq,klmnopqr,lmnopqrs,mnopqrst,nopqrstu,opqrstuv,pqrstuvw,qrstuvwx,rstuvwxy,stuvwxyz,abcdefghi,bcdefghij,cdefghijk,defghijkl,efghijklm,fghijklmn,ghijklmno,hijklmnop,ijklmnopq,jklmnopqr,klmnopqrs,lmnopqrst,mnopqrstu,nopqrstuv,opqrstuvw,pqrstuvwx,qrstuvwxy,rstuvwxyz,abcdefghij,bcdefghijk,cdefghijkl,defghijklm,efghijklmn,fghijklmno,ghijklmnop,hijklmnopq,ijklmnopqr,jklmnopqrs,klmnopqrst,lmnopqrstu,mnopqrstuv,nopqrstuvw,opqrstuvwx,pqrstuvwxy,qrstuvwxyz,abcdefghijk,bcdefghijkl,cdefghijklm,defghijklmn,efghijklmno,fghijklmnop,ghijklmnopq,hijklmnopqr,ijklmnopqrs,jklmnopqrst,klmnopqrstu,lmnopqrstuv,mnopqrstuvw,nopqrstuvwx,opqrstuvwxy,pqrstuvwxyz,abcdefghijkl,bcdefghijklm,cdefghijklmn,defghijklmno,efghijklmnop,fghijklmnopq,ghijklmnopqr,hijklmnopqrs,ijklmnopqrst,jklmnopqrstu,klmnopqrstuv,lmnopqrstuvw,mnopqrstuvwx,nopqrstuvwxy,opqrstuvwxyz,abcdefghijklm,bcdefghijklmn,cdefghijklmno,defghijklmnop,efghijklmnopq,fghijklmnopqr,ghijklmnopqrs,hijklmnopqrst,ijklmnopqrstu,jklmnopqrstuv,klmnopqrstuvw,lmnopqrstuvwx,mnopqrstuvwxy,nopqrstuvwxyz,abcdefghijklmn,bcdefghijklmno,cdefghijklmnop,defghijklmnopq,efghijklmnopqr,fghijklmnopqrs,ghijklmnopqrst,hijklmnopqrstu,ijklmnopqrstuv,jklmnopqrstuvw,klmnopqrstuvwx,lmnopqrstuvwxy,mnopqrstuvwxyz,abcdefghijklmno,bcdefghijklmnop,cdefghijklmnopq,defghijklmnopqr,efghijklmnopqrs,fghijklmnopqrst,ghijklmnopqrstu,hijklmnopqrstuv,ijklmnopqrstuvw,jklmnopqrstuvwx,klmnopqrstuvwxy,lmnopqrstuvwxyz,abcdefghijklmnop,bcdefghijklmnopq,cdefghijklmnopqr,defghijklmnopqrs,efghijklmnopqrst,fghijklmnopqrstu,ghijklmnopqrstuv,hijklmnopqrstuvw,ijklmnopqrstuvwx,jklmnopqrstuvwxy,klmnopqrstuvwxyz,abcdefghijklmnopq,bcdefghijklmnopqr,cdefghijklmnopqrs,defghijklmnopqrst,efghijklmnopqrstu,fghijklmnopqrstuv,ghijklmnopqrstuvw,hijklmnopqrstuvwx,ijklmnopqrstuvwxy,jklmnopqrstuvwxyz,abcdefghijklmnopqr,bcdefghijklmnopqrs,cdefghijklmnopqrst,defghijklmnopqrstu,efghijklmnopqrstuv,fghijklmnopqrstuvw,ghijklmnopqrstuvwx,hijklmnopqrstuvwxy,ijklmnopqrstuvwxyz,abcdefghijklmnopqrs,bcdefghijklmnopqrst,cdefghijklmnopqrstu,defghijklmnopqrstuv,efghijklmnopqrstuvw,fghijklmnopqrstuvwx,ghijklmnopqrstuvwxy,hijklmnopqrstuvwxyz,abcdefghijklmnopqrst,bcdefghijklmnopqrstu,cdefghijklmnopqrstuv,defghijklmnopqrstuvw,efghijklmnopqrstuvwx,fghijklmnopqrstuvwxy,ghijklmnopqrstuvwxyz,abcdefghijklmnopqrstu,bcdefghijklmnopqrstuv,cdefghijklmnopqrstuvw,defghijklmnopqrstuvwx,efghijklmnopqrstuvwxy,fghijklmnopqrstuvwxyz,abcdefghijklmnopqrstuv,bcdefghijklmnopqrstuvw,cdefghijklmnopqrstuvwx,defghijklmnopqrstuvwxy,efghijklmnopqrstuvwxyz,abcdefghijklmnopqrstuvw,bcdefghijklmnopqrstuvwx,cdefghijklmnopqrstuvwxy,defghijklmnopqrstuvwxyz,abcdefghijklmnopqrstuvwx,bcdefghijklmnopqrstuvwxy,cdefghijklmnopqrstuvwxyz,abcdefghijklmnopqrstuvwxy,bcdefghijklmnopqrstuvwxyz,abcdefghijklmnopqrstuvwxyz,

來源

2013-10-23 18:59:40 Cruncher

void printSubstring() { 

    int len = s.length(); 

    for (int i=1;i<len+1;i++) 
    { 
     for (int k=0;k<len-i;k++) 
     System.out.print(s.substring(k,k+i)+", "); 
    } 
    System.out.println(); 
}

來源

2013-10-23 18:50:25

'abcd'給我'a，b，c，ab，bc，abc'作爲輸出。 – Cruncher

你可以嘗試這樣的事情，

void printSubstring(String s){ 
    if(s == null){ 
    return; 
    } 

    for(int lenghtSubstring = 1; lenghtSubstring <= s.length(); lenghtSubstring++){ 
    for(int index = 0; index <= s.length() - lenghtSubstring; index++){ 
     System.out.print(s.substring(index, index + lenghtSubstring) + ","); 
    } 
    } 
}

來源

2013-10-23 18:59:25

內環應該是 -

for (int k=0;k<len-i;k++) 
     System.out.print(s.substring(k,k+i+1)+", ");

希望有所幫助

來源

2013-10-23 19:04:48 ajc

是我的壞... shud是s.substring（k，k + i + 1）+「，」 – ajc

哦，我看到你已經回答了同樣的問題。 :) upvoting你的速度。 – ajc

For循環與子字符串

回答

相關問題