-1
我有一個$ photo_array,我想獲取特定的URL。如何通過php中的複雜數組進行解析
這是我的PHP。我敢肯定,我不是這樣做的權利:
$photo_array = $user_photos->asArray();
foreach($arr as $key => $value)
{
$url = $photo_array["data"]->$key->images->["0"]->source;
echo $url."<br>";
}
這裏是我的數組的副本......見箭頭看到我想要的價值得到。 我怎樣才能做到在foreach必須適用於第一[0] ...所以我只想要1個URL中的每個關鍵
Array
(
[data] => Array
(
[0] => stdClass Object <<<<< FOREACH applies to this key HERE
(
[id] => 123
[created_time] => 2013-04-21T22:22:33+0000
[from] => stdClass Object
(
[id] => 123
[name] => name
)
[height] => 479
[icon] => https://fbstatic-a.akamaihd.net/rsrc.php/v2/yz/r/StEhvv3RhPvjk.gif
[images] => Array
(
[0] => stdClass Object
(
[height] => 1365
***THIS IS WHAT I WANT >>>>> [source] => https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-xpf1/t31.0-8/9034014_10151555782563_1289220490_o.jpg
[width] => 2048
)
[1] => stdClass Object
(
[height] => 960
[source] => https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-xpf1/t31.0-8/p960x960/9032201_101513582563_1480490_o.jpg
[width] => 1440
)
[2] => stdClass Object
(
[height] => 720
[source] => https://fbcdn-sphotos-b-a.akamaihd.net/hphotos-ak-xpf1/t31.0-8/p720x720/903401_101513782563_148970_o.jpg
[width] => 1080
)
)
[link] => https://www.facebook.com/photo.php?fbid=10151351263&set=a.41902562.210698.6182562&type=1
[updated_time] => 2014-11-24T22:43:04+0000
[width] => 720
那...感謝
他只想要一個圖像url。 ''foreach必須應用於第一個[0] ...所以我只需要在每個鍵中輸入1個URL「' – Darren