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我正在使用kendo ui的Listview。我沒有服務器包裝類,我正在使用免費的Web版本。Kendo Ui web列表查看
public ActionResult Index()
{
return View();
}
public ActionResult GetCandidateSearch()
{
IhrmsEntities Entity = new IhrmsEntities();
List<VW_CANDBASICSEARCH> lstCandidateSearch = Entity.VW_CANDBASICSEARCH.Take(50).ToList();
return Json(lstCandidateSearch,JsonRequestBehavior.AllowGet);
}
我index.cshtml
<div>
@Html.Partial("~/Views/Home/PvCandidateBasicSearch.cshtml")
</div>
我PvCandidateBasicSearch.cshtml
<div class="gridHolder" style="width: 100%">
<div id="listCandidateView" class="itemDisplay"></div>
<div id="pager"></div>
</div>
<script type="text/x-kendo-tmpl" id="template">
<div class="itemDisplay">
<div class="text-label">${CAND_NAME} </div>
<div class="text-label">${CAND_LOCATION} </div>
<div class="text-label">${CAND_MOBILE} </div>
<div class="text-label">${CAND_PRE_EMAIL} </div>
<div class="text-label">${CAND_SKILL} </div>
<div class="text-label">${CAND_CITY} </div>
<a href="/Home/EditCandidate?id=${CAND_ID}" >Edit</a>
<a href="/Home/DeleteCandidate?id=${CAND_ID}" >Delete</a>
</div>
</script>
<style type="text/css">
.text-label {
font-size: large;
}
.itemDisplay {
margin: auto;
padding: 6px 8px;
width:auto;
min-width:200px;
height: auto;
min-height:100px;
border: 1px solid #999999;
-webkit-border-radius: 6px;
border-radius: 6px;
font-weight: normal;
background: #deefff;
}
.gridHolder{width: 100%; height:auto; min-height:300px; margin:auto;}
</style>
我在layout.cshtml的JavaScript代碼如下
給出: 我的控制器代碼在下面給出<script type="text/javascript">
var dataSource = new kendo.data.DataSource({
transport: {
read: {
url: '/Home/GetCandidateSearch',
type: "GET",
dataType: "json"
}
},
pageSize: 15
});
$("#pager").kendoPager({
dataSource: dataSource
});
$("#btnSearch").click(function() {
LoadListView();
});
function LoadListView() {
$("#listCandidateView").kendoListView({
dataSource: dataSource,
pageable: true,
template: kendo.template($("#template").html())
});
}
</script>
當我第一次點擊搜索按鈕時,它將完全轉到GetCandidateSearch操作方法並顯示結果。但是當我第二次單擊搜索按鈕時,它不會執行操作方法。 Plz幫助我。
做了以下幫助?如果是這樣,請將其作爲答案 – Martin