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嗨,我有以下查詢,但它仍然給我指定的結果,不給我。這不在什麼地方?mysql不在聲明中,不工作
select taxonomic_units.tsn, hierarchy.hierarchy_string, hierarchy.TSN, taxonomic_units.rank_id from hierarchy left join taxonomic_units on hierarchy.TSN = taxonomic_units.tsn where taxonomic_units.rank_id = 220 and hierarchy.hierarchy_string LIKE '%180211%' and taxonomic_units.tsn not in ('180212') order by rand() limit 1
select taxonomic_units.tsn, hierarchy.hierarchy_string, hierarchy.TSN, taxonomic_units.rank_id from hierarchy left join taxonomic_units on hierarchy.TSN = taxonomic_units.tsn where taxonomic_units.rank_id = 220 and hierarchy.hierarchy_string LIKE '%180210%' and taxonomic_units.tsn not in ('180212,573165') order by rand() limit 1
select taxonomic_units.tsn, hierarchy.hierarchy_string, hierarchy.TSN, taxonomic_units.rank_id from hierarchy left join taxonomic_units on hierarchy.TSN = taxonomic_units.tsn where taxonomic_units.rank_id = 220 and hierarchy.hierarchy_string LIKE '%180130%' and taxonomic_units.tsn not in ('180212,573165,573165') order by rand() limit 1
select taxonomic_units.tsn, hierarchy.hierarchy_string, hierarchy.TSN, taxonomic_units.rank_id from hierarchy left join taxonomic_units on hierarchy.TSN = taxonomic_units.tsn where taxonomic_units.rank_id = 220 and hierarchy.hierarchy_string LIKE '%179913%' and taxonomic_units.tsn not in ('180212,573165,573165,585192') order by rand() limit 1
select taxonomic_units.tsn, hierarchy.hierarchy_string, hierarchy.TSN, taxonomic_units.rank_id from hierarchy left join taxonomic_units on hierarchy.TSN = taxonomic_units.tsn where taxonomic_units.rank_id = 220 and hierarchy.hierarchy_string LIKE '%158852%' and taxonomic_units.tsn not in ('180212,573165,573165,585192,624896') order by rand() limit 1
這裏是重複的結果,我不是在聲明中假設過濾出來,但它沒有。
0 180212
1 573165
2 573165
3 632899
4 632141
5 647171
他顯然不知道下一個號碼 –
@YourCommonSense,但根據他的輸出,這應該是這樣的類型,所以這不是錯誤的。不需要downvote。 –
我該如何在PHP中做到這一點?喜歡這個 ? 「'」。 implode(「','」,$ myArray)。 「'」; – user2604754