JAXB嵌套集合

Question

我遇到了在另一個JAXB對象內映射JAXB對象集合的麻煩，任何人都會在下面看到我的結構有問題？我得到一個空的ArrayList formerUsers使用下面的代碼：

String test="<SSO-Request><User-Id>3119043033121014002</User-Id><Former-User-Ids><User-Id>3119043033121014999</User-Id><User-Id>3119043033121014555</User-Id></Former-User-Ids></SSO-Request>"; 
     SSORequest ssoRequest=null; 
     try{ 
      JAXBContext jaxbContext = JAXBContext.newInstance(SSORequest.class); 
      Unmarshaller unmarshaller = jaxbContext.createUnmarshaller(); 
      ssoRequest = (SSORequest) unmarshaller.unmarshal(new StringReader(test)); 
     } 
     catch(Exception e){ 
      e.printStackTrace(); 
     } 

---

@XmlAccessorType(XmlAccessType.FIELD) 
    @XmlRootElement(name="SSO-Request") 
    public class SSORequest { 
     @XmlElement(name="User-Id") 
     String userId; 
     @XmlElementWrapper(name="Former-User-Ids") 
     List<FormerUser> formerUsers; 
    } 

---

@XmlAccessorType(XmlAccessType.FIELD) 
    @XmlRootElement(name="Former-User-Ids") 
    public class FormerUser { 
    @XmlElement(name="User-Id") 
    String userId; 
} 

Answer 1

你過於複雜的映射，這是所有你需要：

@XmlAccessorType(XmlAccessType.FIELD) 
@XmlRootElement(name="SSO-Request") 
public class SSORequest { 

    @XmlElement(name="User-Id") 
    String userId; 

    @XmlElementWrapper(name="Former-User-Ids") 
    @XmlElement(name="User-Id") 
    List<String> formerUserIds; 
} 

Answer 2

如果房產應該是列表< FormerUser>那麼您將需要aw可以告訴JAXB該ID對應的內容。如果FormerUsers數據將在文檔中出現，那麼你可以使用@XmlID和@XmlIDREF這個映射：

• http://bdoughan.blogspot.com/2010/10/jaxb-and-shared-references-xmlid-and.html

如果FormerUsers數據將文檔外發生，那麼你就可以用我在下面的答案中描述的策略：

• Using JAXB to cross reference XmlIDs from two XML files

Answer 3

你應該要麼改變你的映射，提出skaffman，或者你應該改變的xml：

<SSO-Request><User-Id>3119043033121014002</User-Id><Former-User-Ids><Former-User><User-Id>3119043033121014999</User-Id></Former-User><Former-User><User-Id>3119043033121014555</User-Id></Former-User></Former-User-Ids></SSO-Request> 

和更改的XML FormerUser元素的名稱：

@XmlAccessorType(XmlAccessType.FIELD) 
@XmlRootElement(name="Former-User") 
public class FormerUser { 
    @XmlElement(name="User-Id") 
    String userId; 
}