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有人可以幫我從字符串中去掉字符,只留下「[....]」中的字符嗎?從字符串中提取方括號內的文本
For example:
a = newyork_74[mylocation]
b = # strip the frist characters until you reach the first bracket [
c = [mylocation]
有人可以幫我從字符串中去掉字符,只留下「[....]」中的字符嗎?從字符串中提取方括號內的文本
For example:
a = newyork_74[mylocation]
b = # strip the frist characters until you reach the first bracket [
c = [mylocation]
假設沒有嵌套結構,一種方法是使用itertools.dropwhile
,
>>> from itertools import dropwhile
>>> b = ''.join(dropwhile(lambda c: c != '[', a))
>>> b
'[mylocation]'
另一個是使用regexs
,
>>> import re
>>> pat = re.compile(r'\[.*\]')
>>> b = pat.search(a).group(0)
>>> b
'[mylocation]'
像這樣:
>>> import re
>>> strs = "newyork_74[mylocation]"
>>> re.sub(r'(.*)?(\[)','\g<2>',strs)
'[mylocation]'
你有沒有嘗試過ING? –
'[]是否可以嵌套? – arshajii
這聽起來像是[正則表達式]的工作(http://docs.python.org/2/library/re.html)。 – 2013-06-22 19:41:46