我遇到了一些難以解決的問題。基本上我會搜索一個房間,我會顯示一個符合標準的房間列表(包括分頁)。現在,當我嘗試呼叫房間的圖像時,問題就出現了。第一個圖像將顯示,但不會休息,我得到的錯誤:從視圖中調用函數解決不可預見的視圖
A PHP Error was encountered Severity: Notice
Message: Undefined offset: 0
Filename: views/search_view.php
Line Number: 27
A PHP Error was encountered Severity: Notice
Message: Trying to get property of non-object
Filename: views/search_view.php
Line Number: 27
這是我迄今所做
我的模型:
function get_room_image($rid)
{
$q = $this->db
->where('room_id',$rid)
->limit(1)
->get('room_image');
return $q->result();
}
function search_rooms()
{
$q = $this->db
->where('features', $this->input->post('features'))
->get('rooms');
$room['results'] = $q->result();
return $room['results'];
}
我的控制器:
function search()
{
$data['main_content'] = 'search_view';
$data['page_title'] = 'Search';
$data['results'] = $this->site_model->search_rooms();
$this->load->view('includes/template',$data);
}
我的看法:
...
<?php foreach ($results['results'] as $room) {
$room_images = $this->site_model->get_room_image($room->id); ?>
<div class="col2 bot">
<div class="col_head"></div>
<div class="col_info">
<table border="0" cellpadding="5" cellspacing="5">
<tr><td>
<img src="<?php echo base_url() . 'room/' . $room_images[0]->image_name; ?>" border="0" class="imgbox" />
</td>
...
線27實際上是與它的img標籤行
當我的要求,我得到以下一的var_dump:
array(1) {
[0]=>
object(stdClass)#27 (3) {
["id"]=>
string(1) "1"
["room_id"]=>
string(1) "1"
["image_name"]=>
string(36) "1614d828817ac5b396660621048b167a.jpg"
}
}
array(0) {}
array(0) {}
array(0) {}
...
這樣看來,它不執行get_room_image每次迭代的功能都正確
任何建議是最受歡迎的。
Regards,
嘗試在該行上執行var_dump($ room_images) - 查看實際存在的內容。我猜[0]的索引是錯誤的一些變量 – Laurence