在繼續使用函數C＃Unity之前等待協程完成

Question

我正在努力使單元在Unity2d中通過網格移動。我得到了運動沒有問題的工作。 我希望MovePlayer函數等到協程完成後再繼續下去，所以程序會一直等到玩家完成移動後再發出更多的訂單。

這裏是我的代碼： 公共類球員：MonoBehaviour {

public Vector3 position; 
private Vector3 targetPosition; 

private float speed; 

void Awake() 
{ 
    speed = 2.0f; 
    position = gameObject.transform.position; 
    targetPosition = position; 
    GameManager.instance.AddPlayerToList(this);      //Register this player with our instance of GameManager by adding it to a list of Player objects. 
} 

//Function that moves the player, takes a list of nodes as path 
public void MovePlayer(List<Node> path) 
{ 
    StartCoroutine(SmoothMovement(path)); 
    //Next step should wait until SmoothMovement is finished 
} 

private IEnumerator SmoothMovement(List<Node> path) 
{ 
    float step = speed * Time.deltaTime; 

    for (int i = 0; i < path.Count; i++) 
    { 
     targetPosition = new Vector3(path[i].coordinatesX, path[i].coordinatesY, 0f); 

     float sqrRemainingDistance = (transform.position - targetPosition).sqrMagnitude; 

     while (sqrRemainingDistance > float.Epsilon) 
     { 
      transform.position = Vector3.MoveTowards(transform.position, targetPosition, step); 
      sqrRemainingDistance = (transform.position - targetPosition).sqrMagnitude; 
      yield return null; 
     } 

     position = transform.position; 
    } 

} 

Answer 1

你不能等待在主線程功能的協同程序，否則你的遊戲將凍結，直到你的函數結束。

爲什麼不在協同程序結束時調用下一步？

private IEnumerator SmoothMovement(List<Node> path) 
{ 
    float step = speed * Time.deltaTime; 

    for (int i = 0; i < path.Count; i++) 
    { 
     targetPosition = new Vector3(path[i].coordinatesX, path[i].coordinatesY, 0f); 

     float sqrRemainingDistance = (transform.position - targetPosition).sqrMagnitude; 

     while (sqrRemainingDistance > float.Epsilon) 
     { 
      transform.position = Vector3.MoveTowards(transform.position, targetPosition, step); 
      sqrRemainingDistance = (transform.position - targetPosition).sqrMagnitude; 
      yield return null; 
     } 

     position = transform.position; 
    } 
    //Next Step 
}