如何設置一個Timer來控制循環內的函數調用？

Question

我有這個function，發揮Spotify：

#a function to play Spotify 
def play(id_): 
    print 'playing', id_ 
    os.system("osascript -e 'tell application \"Spotify\" to play track \"%s\"'" % (id_,)) 

及以下loop，通過所有playlist歌曲，其迭代，獲得所有可播放id的（foreign_id），將它們傳遞給play(id_)，

和將每首歌曲duration轉換爲time.sleep()以停止循環，直到每首歌曲結束爲止，重複循環：

for i, song in enumerate(song_playlist): 
      #we need to track each song id 
      song_id = song_playlist[i]['id'] 
      #in order to get song 'duration', access 'song/profile response' and pass the id as an argument 
      response_profile = en.get('song/profile', id=song_id, bucket="audio_summary") 
      song_profile = response_profile['songs'] 
      dur = song_profile[0]['audio_summary']['duration'] 
      #convert to miliseconds  
      dur *= 1000 
      print int(round(dur))       
      #now we access each song 'foreign_id' 
      for track in song: 
       track = song['tracks'][i] 
       track_id = track['foreign_id'].replace('-WW', '')   
      print '{0} {2} {1}'.format(i, song['artist_name'], song['title']) 
      #call the function for each track 
      play(track_id) #CALL FUNCTION HERE 
      time.sleep(int(round(dur))) # SET INTERVAL CALL TO EACH SONG DURATION 

然而，只有一首歌曲播放，遞歸消失。

我該如何更正代碼，以便我可以使用功能按順序播放所有曲目，只能運行一次代碼？

Answer 1

它看起來像play(track_id)應該在for track in song循環內。你需要縮進1級。

for i, song in enumerate(song_playlist): 
    # Code as before ... 
    for track in song: 
     track = song['tracks'][i] 
     track_id = track['foreign_id'].replace('-WW', '')   
     print '{0} {2} {1}'.format(i, song['artist_name'], song['title']) 
     play(track_id) #CALL FUNCTION HERE 
    time.sleep(int(round(dur))) # SET INTERVAL CALL TO EACH SONG DURATION