如何刪除陣列的PHP的值

Question

請幫助 時，我想喲當我打印陣列之後從陣列布歐中刪除一個元素它顯示錯誤注意未定義偏移：3行號16

<?php 
    $value = 22; 
    $numbers = array(4, 6, 2, 22, 11); 
    $arrlength = count($numbers); 

    for($y = 0; $y < $arrlength ; $y++) { 
     if ($numbers[$y] == $value) { 
      unset($numbers[$y]); 
     } 
    } 
    $arrlength = count($numbers); 
    for($x = 0; $x < $arrlength; $x++) { 
     echo $numbers[$x]; 
     echo "<br>"; 
    } 
?> 

Answer 1

您應該使用「array_values（）」重新索引數組。你可以在這裏找到解釋：http://php.net/manual/en/language.types.array.php#language.types.array.useful-funcs

Answer 2

使用array_values()。

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
if ($numbers[$y] == $value) { 
    unset($numbers[$y]); 
} 
} 
$numbers = array_values($numbers); 
$arrlength = count($numbers); 
for($x = 0; $x < $arrlength; $x++) { 
echo $numbers[$x]; 
echo "<br>"; 
} 
?> 

檢查在線演示：Click Here

OR

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
if ($numbers[$y] == $value) { 
    unset($numbers[$y]); 
} 
} 
//$numbers = array_values($numbers); 
//$arrlength = count($numbers); 
foreach($numbers as $key=>$num) { 
echo $num; 
echo "<br>"; 
} 
?> 

Answer 3

你要打印不存在關鍵

的元素試試這個：

<?php 
$value = 22; 
$numbers = array(4, 6, 2, 22, 11); 
$arrlength = count($numbers); 

for($y = 0; $y < $arrlength ; $y++) { 
    if ($numbers[$y] == $value) { 
     unset($numbers[$y]); 
    } 
} 
foreach($numbers as $k => $number) 
    echo "key: ". $k . " value: ". $number . "<br />";