如何將uwsgi命令行轉換爲yaml文件？

Question

如何將以下命令放入app.yaml文件中。我想知道我做錯了什麼？

uwsgi --socket 127.0.0.1:3000 --file /home/james/james-api/runserver.py --callable app --processes 2 

這低於YAML文件：

uwsgi: 
    socket: 127.0.0.1:3000 
    python-path: /home/james/james-api/ 
    callable: runserver:app 
    processes: 2 
    pidfile: /tmp/uwsgi.pid 
    daemonize: /var/log/uwsgi.log 
    master: 1 
    workers: 2 
    chmod-socket: 666 
    auto-procname: 1 

Answer 1

我所要做的就是去除 -

uwsgi: 
    socket: 127.0.0.1:3000 
    file: /home/james/james-api/runserver.py 
    python-path: . 
    callable: app 
    processes: 2 
    master: 1 
    workers: 2 
    chmod-socket: 666 
    auto-procname: 1 
    pidfile: /tmp/uwsgi.pid 
    daemonize: /var/log/uwsgi.log