retreive JSON格式的JSON數據格式JS

輸出值retreive JSON格式的JSON數據格式JS

[{ 
    "school_id": "248", 
    "server_url": "http:\/\/testdummy.brainyknights.in\/AndroidAppv5\/", 
    "school_id_string": "jayanagar", 
    "logo_path": "0", 
    "about": "all" 
}]

如何檢索的價值學校ID在JS？

來源

2017-04-11 priya

是雙向

let data = [{"school_id":"248","server_url":"http:\/\/testdummy.brainyknights.in\/AndroidAppv5\/","school_id_string":"jayanagar","logo_path":"0","about":"all"}];

之一：

data[0].school_id

data[0]['school_id']

來源

2017-04-11 04:49:05

謝謝你。代碼正在工作 – priya

你必須先解析JSON：

var obj = JSON.parse("...you json string here"); 
// This will return you the school id of the fisrt entry of your array. 
var school_id = obj[0].school_id;

來源

2017-04-11 04:46:02 Christos

'obj'出現陣列給我... – Rayon

@Rayon我做了一個更正。謝謝 – Christos

您可以使用此：

let data = [{ 
 
    "school_id": "248", 
 
    "server_url": "http:\/\/testdummy.brainyknights.in\/AndroidAppv5\/", 
 
    "school_id_string": "jayanagar", 
 
    "logo_path": "0", 
 
    "about": "all" 
 
}]; 
 

 
console.log(data[0].school_id); // use this if just one object in array 
 
console.log(`-----------------------------------------------`) 
 
data.forEach(o=>console.log(o.school_id)); // use this if more than one objects in array

如果您的數組中有一個對象，那麼你可以針對它的[0] th索引來獲得目標對象的期望屬性。否則，如果有多個對象，則必須遍歷每個對象。

來源

2017-04-11 04:48:26 Jai

這將讓你從你的JSON的schoolid

var t = JSON.parse('{"school_id": "248", "server_url": "http:\/\/testdummy.brainyknights.in\/AndroidAppv5\/", "school_id_string": "jayanagar", "logo_path": "0", "about": "all"}'); 
 
alert(t['school_id'])

來源

2017-04-11 05:53:50

retreive JSON格式的JSON數據格式JS

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