如何返回基於過濾器的新對象？

Question

我有這個JS：

var json = {"products":[{"id":"6066157707315577","reference_prefix":"BB","name":"BeanieBaby","product_line":false,"has_ideas":true},{"id":"6066197229601550","reference_prefix":"BBAGS","name":"BlackBags","product_line":false,"has_ideas":false}],"pagination":{"total_records":4,"total_pages":1,"current_page":1}} 

var stuff = json.products.filter(function(obj) { 
    return obj.has_ideas === true 
}); 

console.log(stuff); 

我需要幫助返回一個js OBJ在它開始於（VAR JSON = {「產品」：...）相同的格式，但只包含過濾的對象，如果他們存在。如果不是，我只想要一個空數組。我該怎麼做呢？

Answer 1

只需創建你的對象，並在其「產品」屬性填寫：

var jsonObj = {"products":[{"id":"6066157707315577","reference_prefix":"BB","name":"BeanieBaby","product_line":false,"has_ideas":true},{"id":"6066197229601550","reference_prefix":"BBAGS","name":"BlackBags","product_line":false,"has_ideas":false}],"pagination":{"total_records":4,"total_pages":1,"current_page":1}} 

var stuff = {}; 
stuff.products = jsonObj.products.filter(function(obj) { 
    return obj.has_ideas === true 
}); 

console.log(stuff);