如何合羣在卡諾圖細胞

Question

我在卡諾圖的分類有些問題，我不知道怎麼定義卡諾表中的各種情況，

，如果我連續使用「如果」和「其他」的聲明，我認爲這是非常低級的編程，我想要一些算法，將被稱爲品種本身，還是少用「如果」和「其他」的語句 這裏我有卡諾圖的一些分類例如：

我的程序必須知道，這兩個「1」在一個類別中，並且將被分類爲 我怎麼能反覆灌輸這我的計劃，我怎樣才能實現這種分類 這是我的兩個變量卡諾圖碼：

int num_var;  // stores the number of variables entered by user 
int squ_4[4];  // variable used for a 1-D array for the 4 square Karnaugh map 
int a,b,c;   // variables for entering and checking values in Karnaugh map squares 
char var_name[10]; // character string array 

strcpy(var_name,"ABCDRSXYZ"); // character string for variable name 

printf("\nThis program works out a Boolean function for a 2,3 and 4 variable Karnaugh map.\n\n"); 

cout << "Enter number of Karnaugh map variables (2,3 or 4) required: "; 
cin >> num_var; 
do 
{ 
    if(num_var>4) 
    { 
     printf("\n Sorry, you have chosen too many variables \n"); 
     printf("\n Please enter 2,3 or 4 variables: "); 
     cin >> num_var; 
    } 
    if(num_var<2) 
    { 
     printf("\n Sorry, not enough variables chosen \n"); 
     printf("\n Please enter 2,3 or 4 variables: "); 
     cin >> num_var; 
    } 
}while(num_var>4 || num_var<2); 

do 
{ 
    printf("\nVariables are: %c %c \n",var_name[4],var_name[5]); // output variable names 

    printf("\n Please enter value in Karnaugh map square and press RETURN \n") 

    for(a=0;a<4;a++) 
    { 
     printf("\nEnter 1 or 0 into square %d: ",a); 
     cin >> squ_4[a]; // store value into array 

     while(squ_4[a]!=0 && squ_4[a]!=1) 
     { 
      printf("\n Value entered in Karnaugh map square %d, was not 1 or 0 \n",a); 
      printf("\nPlease enter 1 or 0 into square %d: ",a); 
      cin >> squ_4[a]; 
     } 
    } 
    printf("\nYour Karnaugh map is: \n\n\t\t  %c'%c \n\t\t %c'%d %d\n\t\t %c %d %d \n",var_name[5],var_name[5],var_name[4],squ_4[0],squ_4[1],var_name[4],squ_4[2],squ_4[3]); 


    if(squ_4[0]==0 && squ_4[1]==0 && squ_4[2]==0 && squ_4[3]==0) 
    { 
     printf("\nThere is no function from the Karnaugh map\n\n"); 
     return 0; 
    } 
    printf("\nThe Boolean function is: \n\n "); 

    if(squ_4[0]==1) 
    { 
     printf("%c'%c' ",var_name[4],var_name[5]); 
     if(squ_4[1]==1 || squ_4[2]==1 || squ_4[3]==1) 
     { 
      printf("+ "); 
     } 
    } 
    if(squ_4[1]==1) 
    { 
     printf("%c'%c ",var_name[4],var_name[5]); 
     if(squ_4[2]==1 || squ_4[3]==1) 
     { 
      printf("+ "); 
     } 
    } 
    if(squ_4[2]==1) 
    { 
     printf("%c%c' ",var_name[4],var_name[5]); 
     if(squ_4[3]==1) 
     { 
      printf("+ "); 
     } 
    } 
    if(squ_4[3]==1) 
    { 
     printf("%c%c ",var_name[4],var_name[5]); 
    } 

    cout << "\n\n\n\n"; 
}while(num_var==2); 

Answer 1

商店他們的回答某些變量，並通過使用循環的結果進行比較。