2017-10-04 41 views
0

我是socket編程新手。我必須編寫一個程序,其中客戶端接受用戶的文件名並將其發送到服務器。服務器讀取相應的文件並將其內容發送回客戶端。現在我的問題是服務器程序凍結'String file = br.readLine()'。當我終止我的客戶端程序時,會執行更多的服務器代碼。如果我在客戶端代碼的末尾註釋掉while循環,則服務器代碼完美無缺(將數據打印到標準輸出)。你能告訴我的代碼有什麼問題嗎? 服務器代碼:爲什麼服務器程序在線上凍結'String file = br.readLine()'?

public class SocketServer { 

    public static void main(String[] args) throws Exception{ 
     System.out.println("Server is started."); 
     ServerSocket ss = new ServerSocket(9999); 

     System.out.println("Server is waiting for a client."); 
     Socket server = ss.accept(); 

     System.out.println("Client is connected."); 

     BufferedReader br = new BufferedReader(new InputStreamReader(server.getInputStream())); 
     String file = br.readLine(); 

     System.out.println("Requested file is: " + file); 

     OutputStreamWriter os = new OutputStreamWriter(server.getOutputStream()); 
     PrintWriter writer = new PrintWriter(os); 

     BufferedReader fr = new BufferedReader(new FileReader(file)); 

     String line; 
     while((line = fr.readLine()) != null) { 
      writer.write(line); 
      writer.flush(); 
      System.out.println(line); 
     } 
    } 
} 

客戶端代碼:

public class SocketClient { 

    public static void main(String[] args) throws Exception { 
     Scanner in = new Scanner(System.in); 
     Socket client = new Socket("localhost", 9999); 

     OutputStreamWriter os = new OutputStreamWriter(client.getOutputStream()); 
     PrintWriter writer = new PrintWriter(os); 

     System.out.print("Enter filename: "); 
     String file = in.nextLine(); 

     writer.write(file); 
     writer.flush(); 

     BufferedReader br = new BufferedReader(new InputStreamReader(client.getInputStream())); 

     System.out.println("Content of " + file + ":"); 

     String str; 
     while((str = br.readLine()) != null) { 
      System.out.print(str); 
     } 
     System.out.println("File transfer is complete."); 
    } 

} 
+0

您需要一個調試器。 – notyou

+0

我使用了一個調試器。它向我展示了服務器程序凍結的路線。 –

回答

3

br.readLine();將等待輸入直到它找到一個新的行。

writer.write(file);您正在寫入沒有換行的文件名。

所以爲了使它工作,要麼在客戶端寫一個換行字符,要麼在服務器上用char字符讀取它。

希望這會有所幫助。

+0

謝謝。它有幫助。 –

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