我有一個簡單的Javascript驗證代碼,如果我將它發送到某個PHP地址,它工作正常,但如果我將它發送到我創建的PHP頁面,則驗證代碼無效。Javascript驗證在我的PHP中不起作用
該代碼目前非常基本,並使用正則表達式驗證某些字段。
基本上,如果我用給定的現成PHP文件(我無法訪問)嘗試它,它工作正常呈現我的錯誤對話框,直到所有的字段都是正確的。同時,在我製作的PHP頁面中,它捕獲錯誤,顯示對話框,但在OK警告框中單擊,它將字段提交給我的PHP文件。
有人能告訴我發生了什麼嗎?
謝謝。
這是JavaScript:
<script type="text/javascript">
/* <![CDATA[ */
// this function calls all the other functions that validate each field of the submitting form
function validate() {
var validated = false;
validated = validateRId() && validateEId();
return validated;
}
// this validates the RID: checking that the field is filled with a number between 1 //and 99999
function validateRId() {
var RIdElement = document.getElementById("RID");
patternRId = /^([1-9][0-9]{0,4})$/;
if (patternRId.test(RIdElement.value)) {
return true;
} else {
alert ("Please Enter your RID (a number range 1 to 99999))");
RIdElement.focus();
return false
}
}
// this validates the EventID: checking that the field is filled with a number between 1 and 99999
function validateEId() {
var EIdElement = document.getElementById("EID");
patternEId = /^([1-9][0-9]{0,4})$/;
if (patternEId.test(EIdElement.value)) {
return true;
} else {
alert ("Please Enter the EID (a number range 1 to 99999))");
EIdElement.focus();
return false
}
}
/* ]]> */
</script>
<p/>
<form action="http://adress.php" method="post" name="submitrunnertime" onsubmit = "return validate()">
<table>
<tr><td>Runner ID*</td>
<td><input type="text" name="RID" id="RID" size="5" maxlength="5"/></td>
</tr>
<tr><td>Event ID*</td>
<td><input type="text" name="EID" id="EID" size="5" maxlength="5"/></td>
</tr>
</table>
<input type="submit" name="submit" value="submit"/>
<hr/>
</form>
</body>
</html>
這是PHP:
<body>
<?php
// access details as variables
$username = "xxxx";
$password = "tttt";
$hostname = "rrrrr";
//connection
$connection = mysql_connect($hostname, $username, $password) or die ('connection problem:' . mysql_error());
echo $connection . "CONNECTION SUCCEDED<br><br><br>";
//select a database
$mydb = mysql_select_db("xxxx", $connection)or die ('db problem:' . mysql_error());
echo $mydb . " DB SELECTED <br><br><br>";
?>
</body>
</html>
「驗證」功能中存在明顯的語法錯誤。請確保您已經採取了基本的調試步驟,例如在發佈問題之前檢查瀏覽器的錯誤控制檯。 – Pointy
對不起,只是複製並粘貼錯誤。我的函數在語法上應該如下所示:{... && validateEId();返回驗證;} – user2396361