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我一直停留在這個整天使用Parse.com檢索圖像filess。我嘗試了所有其他可用的方法來完成此操作。下面的方法幾乎完成了這項工作,但是它爲變量文件提供了空指針異常。儲蓄與Android的
下面的代碼描述瞭如何保存數據
final ParseObject post = new ParseObject("Student");
post.put("name", nameS);
final ParseFile file = new ParseFile("photo.png", data);
file.saveInBackground(new SaveCallback() {
@Override
public void done(ParseException e) {
post.put("studentPhoto", file);
Log.d("John", ""+ file);
}
});
post.put("author", ParseUser.getCurrentUser());
post.saveInBackground(new SaveCallback() {
public void done(ParseException e) {
if (e == null) {
// Saved successfully.
Toast.makeText(getApplicationContext(), "Saved", Toast.LENGTH_SHORT).show();
Intent intent = new Intent(AddStudentActivityEditText.this, AddStudentActivityTextView.class);
startActivity(intent);
} else {
// The save failed.
Toast.makeText(getApplicationContext(), "Failed to Save", Toast.LENGTH_SHORT).show();
Log.d(getClass().getSimpleName(), "User update error: " + e);
}
}
});
下面的數據介紹了有關檢索數據
final ParseQuery<ParseObject> query = ParseQuery.getQuery("Student");
query.whereEqualTo("author", ParseUser.getCurrentUser());
query.findInBackground(new FindCallback<ParseObject>() {
@Override
public void done(List<ParseObject> objects, ParseException e) {
if (e == null) {
for (ParseObject text : objects) {
name.setText(text.getString("name"));
}
ParseQuery<ParseObject> query = ParseQuery.getQuery("Student");
query.whereEqualTo("author", ParseUser.getCurrentUser());
query.getFirstInBackground(new GetCallback<ParseObject>() {
public void done(ParseObject object, ParseException e) {
if (object != null) {
ParseFile file = (ParseFile)object.get("studentPhoto");
file.getDataInBackground(new GetDataCallback() {
public void done(byte[] data, ParseException e) {
if (e == null) {
Bitmap bitmap = BitmapFactory.decodeByteArray(data, 0, data.length);
//use this bitmap as you want
photo.setImageBitmap(bitmap);
} else {
// something went wrong
}
}
});
} else {
Toast.makeText(getApplicationContext(), "Exception", Toast.LENGTH_SHORT) .show();
}
}
});
} else {
Toast.makeText(getApplicationContext(), "Exception", Toast.LENGTH_SHORT).show();
}
}
});
有學生列,但不是有什麼聯繫,也得到了一些東西,它的類型是字節 – johnrao07
嗯,應該有一個學生表,而不是列。並且在該表中應該是名爲studentPhoto的列。 –
是啊,到底....但沒有任何聯繫,它的類型是字節...我會嘗試你的方法晚些時候,讓你知道 – johnrao07