PHP和MySQL的總行數與條件

Question

我有一個問題，以獲得條件總計行數。這是我的代碼

$pagesize = 10; 
$recordstart = (int)$_GET['recordstart']; 
$recordstart = (isset($_GET['recordstart'])) ? $recordstart : 0; 

$town = $_GET['label_town']; 
$sub = ucfirst($_GET['label_sub']); 

這是我的選擇條件。我也使用這個條件來計算總計數

if (isset($_GET['label_town']) === true && isset($_GET['label_sub']) === true) { 
$where = "WHERE p.label_town = '$town' AND p.label_sub = '$sub' AND `visible` = 1"; 
} else if (isset($_GET['label_town']) === true && isset($_GET['label_sub']) === false) { 
$where = "WHERE p.label_town = '$town' AND `visible` = 1"; 
} else { 
$where = "WHERE `visible` = 1"; 
} 

// Selecting data 
$all_page_index = mysql_query("SELECT p.page_id, p.timestamp, p.label_town, p.label_sub, p.ime_nekretnine, p.mjesto, p.cijena_noc, p.krevet_apart, p.broj_apart, p.min_nocenja, p.description, p.visits, i.image_id, i.page_id, i.ext 
FROM data_page AS p 
LEFT JOIN (
SELECT MAX(image_id) AS max, page_id 
FROM images 
GROUP BY page_id 
) AS n ON p.page_id = n.page_id 
LEFT JOIN images AS i ON i.image_id = n.max 
$where 
ORDER BY p.page_id DESC 
LIMIT $recordstart, $pagesize"); 

// Counting rows with conditions 
function totalrows() { 
    return mysql_result(mysql_query("SELECT COUNT(p.page_id) FROM data_page AS p $where"), 0); 
} 

選擇和顯示數據工作正常，但問題是與選擇計數。總是計算總數不管條件如何。我在哪裏做錯了？

謝謝！

Answer 1

您的COUNT位於函數定義內，其中$where未定義。您需要將其作爲參數傳遞或將查詢移到該函數之外。